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Tom [10]
3 years ago
15

Find the volume of each solid figure

Mathematics
1 answer:
Naddik [55]3 years ago
3 0
Your answer is 270 hope this helps
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\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\&#10;\left. \qquad \qquad \right.(\textit{payments at the end of the period})&#10;\\\\&#10;A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \qquad &#10;\begin{cases}&#10;A=&#10;\begin{array}{llll}&#10;\textit{accumulated amount}\\&#10;\end{array}\to &&#10;\begin{array}{llll}&#10;8000&#10;\end{array}\\&#10;pymnt=\textit{periodic payments}\\&#10;r=rate\to 5\%\to \frac{5}{100}\to &0.05\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{monthly, thus twelve}&#10;\end{array}\to &12\\&#10;t=years\to &4&#10;\end{cases}

\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]&#10;\\\\\\&#10;\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt&#10;\\\\\\&#10;\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt
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