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Mekhanik [1.2K]
3 years ago
9

Help me please, It is due today!

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

Step-by-step explanation:

acct 1

2500 X 1.06^10 is 4,477

acct 2

2500 X 1.04^10 is 3700

choose account 1 because it'll have 4477 after 10 yes and account 2 is 3700

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2 14 in the lowest terms
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Solutions 

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2 ÷ 2 = 1 
14 ÷ 2 = 7 

1/7 is in lowest terms 
 
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SOLVING EACH SYSTEM BY ELIMINATION <br><br><br> x+3y=5 x=-6y+14<br><br><br> HELP
nata0808 [166]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

Step-by-step explanation:

Given the system of the equations

x+3y=5;\:x=-6y+14

solving by elimination method

\begin{bmatrix}x+3y=5\\ x=-6y+14\end{bmatrix}

\mathrm{Arrange\:equation\:variables\:for\:elimination}

\begin{bmatrix}x+3y=5\\ x+6y=14\end{bmatrix}

x+6y=14

-

\underline{x+3y=5}

3y=9

\begin{bmatrix}x+3y=5\\ 3y=9\end{bmatrix}

solve 3y=9 for y:

3y=9

\frac{3y}{3}=\frac{9}{3}

y=3

\mathrm{For\:}x+3y=5\mathrm{\:plug\:in\:}y=3

Solve x+3\cdot \:3=5 for x:

x+3\cdot \:3=5

x+9=5

x=-4

Therefore,

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=-4,\:y=3

6 0
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