The third answer
1 quarter, 6 dimes, 1 nickel, 7 pennies
Answer:
The price of the admission is 15.
Step-by-step explanation:
From the information given, you can write the following equations:
a+3e=45 (1)
a+5e=65 (2), where:
a is the admission cost
e is the exhibition cost
First, you can solve for a in (1):
a=45-3e (3)
Second, you can replace (3) in (2):
45-3e+5e=65
45+2e=65
2e=65-45
2e=20
e=20/2
e=10
Finally, you can replace the value of e in (3):
a=45-3e
a=45-3(10)
a=45-30
a=15
According to this, the price of the admission is 15.
Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
Answer:
(15, 36, 39)
Step-by-step explanation:
Using pythagoreas formula: A^2 * B^2 = C^2
so a=15, b=36, c=39
15^2+36^2=39^2
