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Anestetic [448]
3 years ago
8

I need help with this math test question.

Mathematics
1 answer:
Paraphin [41]3 years ago
3 0

Answer:

since there is no y intercept, it means it will go through the origin (the center of graph). You have to graph 1 to the right, then 4 up. and keep doing that until the end of the graph.

Step-by-step explanation:

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In Mrs. Hu’s classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet, 2/3 have a cat as a pe
tresset_1 [31]
2/3 of the 4/5 of the class has a dog and a cat. Just multiply
(2/3)(4/5)=8/15
45*(8/15)=24
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3 years ago
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!!!I WILL MARK BRAINLIEST! PLZ ANSWER ASAP AND EXPLAIN! VERY IMPORTANT!!
Nata [24]

Answer: Check explanation

Step-by-step explanation: (3,-5), because that's the point where the two lines intersect.

Y=-2x+1

Y=-3/2x-1/2

Substitute the Y to get -2x+1=-3/2x-1/2

1/2x=3/2

x = 3

Now plug x into first equation: y=-2*3+1=-5

so the intersection point is (3,-5)

3 0
2 years ago
Can someone help me please
docker41 [41]
0 there are no odd number 1-15
5 0
3 years ago
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Find an integer value of b that makes x^2 + bx - 81 factorable.
Kaylis [27]

Answer:

b = 80

Step-by-step explanation:

Given that,

x² + bx - 81

To find,

value of b

What is factorable?

A polynomial equation with highest degree 2 is if factorable when

  1. we can find two terms which when multiples = -81x²,   <em> ( x² * - 81 = -81x² ) </em>
  2. and when add = bx

possible factors:

  1. -1x * 81x = -81x²   (Accepted)
  2. 1x * -81x= -81x²    (rejected)
  3. 9x * -9x = -81x²    (rejected)
  4. -9x * 9x = -81x²    (rejected)

Only when -1x , 81x is added -1x + 81x = 80x

so, bx = 80x

     b   = 80

<h3>The equation is x² + 80x - 81</h3>

5 0
2 years ago
What are the solutions of x² + 6x - 6 = 10?
Likurg_2 [28]

Answer: x=- 8 or x=2


Step-by-step explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. The quadratic  equation is:

x^{2}+6x-6-10=0\\x^{2}+6x-16=0

3. Then:

a=1

b=6

c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

x=\frac{6+/-\sqrt{6^{2}-4(1)(-16)}}{2(1)}

x_1=-8\\x_2=2


4 0
3 years ago
Read 2 more answers
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