Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
Hey there! :)
Answer:
(5, -2), or x = 5 and y = -2.
Step-by-step explanation:
We can solve the two equations algebraically by eliminating a variable:
2x + 5y = 0
3x - 4y = 23
Eliminate the x variable by finding the least common multiple and multiplying both equations:
3(2x + 5y = 0)
2(3x - 4y = 23)
Distribute and subtract the bottom equation from the top:
6x + 15y = 0
6x - 8y = 46
------------------
0x + 23y = -46
23y = -46
y = -2.
Plug in y into an equation to solve for x:
2x + 5(-2) = 0
2x - 10 = 0
2x = 10
x = 5. Therefore:
The solution to this equation is (5, -2), or x = 5 and y = -2.
Since p = x² - 7, you can substitute/plug in p for x² - 7
So:
(x² - 7)² - 4x² + 28 = 5
(p)² - 4x² + 28 = 5 You can factor out -4 from (-4x² + 28)
p² - 4(x² - 7) = 5 Plug in p
p² - 4p = 5 Subtract 5
p² - 4p - 5 = 0 Your answer is C
Write a proportion first, change over original, like this:
8 x
16 100
(I got 8 because the difference between 24 and 16 is 8 and I got 100 because percents are out of 100.)
Cross multiply 8 by 100 and you get 800.
Divide 800 by 16 and you get 50.
It changed by 50%
