Suppose that r (cos(θ) + i sin(θ)) is a third root of 27 (cos(π/5) + i sin(π/5)), i.e.
[r (cos(θ) + i sin(θ))]³ = 27 (cos(π/5) + i sin(π/5))
Expand the left side using de Moivre's theorem:
r³ (cos(3θ) + i sin(3θ)) = 27 (cos(π/5) + i sin(π/5))
Matching up real and imaginary parts, we have
r³ cos(3θ) = 27 cos(π/5)
r³ sin(3θ) = 27 sin(π/5)
Right away we see that r³ = 27 ⇒ r = 3, which eliminates A.
We also have
(r³ sin(3θ)) / (r³ cos(3θ)) = (27 sin(π/5)) / (27 cos(π/5))
tan(3θ) = tan(π/5)
3θ = tan⁻¹(tan(π/5))
3θ = π/5 + nπ
(where n is an integer)
θ = π/15 + nπ/3
Now,
• n = 0 ⇒ θ = π/15 ⇒ D is a third root
• n = 1 ⇒ θ = π/15 + π/3 = 2π/5
• n = 2 ⇒ θ = π/15 + 2π/3 = 11π/15 ⇒ C is a third root
Answer:
The company uses it to identify their 600 MOST LOYAL customers. The sample is biased; the population is the loyal customers from it's database.
Simply find the area under the velocity curve. Over the first 3 second interval, the area is that of a trapezoid with bases 2 and 5, so that area/distance traveled is 
. For the last 4 seconds, the area/distance is 
.
Then the total distance traveled is
Answer:
x = 1 11/15
Step-by-step explanation:
Using ratios of similar triangles
3 5.2
-------- = ----------
4 (5.2 + x)
Using cross products
3 * (5.2 + x) = 5.2 * 4
Distribute
15.6 + 3x = 20.8
Subtract 15.6 from each side
15.6-15.6 + 3x = 20.8 -15.6
3x =5.2
Divide each side by 3
3x/3 = 5.2/3
x = 5.2/3
x=52/30
x = 26/15
x = 1 11/15
