3 years ago

Round 2.438 to the nearest tenth

Mathematics

2 answers:

madam [21]3 years ago

6 0

The answer would be 0.02438 to the nearest tenth. Hope this helps :)

igomit [66]3 years ago

5 0

2.438 to the nearest tenth is simply 2.4. The reason being is that the number to the right of the tenth is not 5 bigger than 5. 5 or more raise the score, 4 or less give it a rest.

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Please help ASAP!

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First, recall that

$\sin(-\theta)=-\sin\theta$

So if $\sin(-\theta)=\dfrac15$ , then $\sin\theta=-\dfrac15$ .

Second,

$\tan\theta=\dfrac{\sin\theta}{\cos\theta}$

We know that $\tan\theta>0$ and $\sin\theta$ , which means we should also have $\cos\theta$ .

Third,

$\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\pm\sqrt{1-\sin^2\theta}$

but as we've already shown, we need to have $\cos\theta$ , so we pick the negative root.

Finally,

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