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CaHeK987 [17]
3 years ago
6

Describe the transformation that maps the pre-image (AA) to the image (AA).

Mathematics
1 answer:
asambeis [7]3 years ago
8 0

Answer:

it is reflection on y-axis

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Evaluate ∫ xe2x dx. 1 2 3x A./xe +C 6 B.1/xe2x-1/ xe2x+C 22 C.1/xe2x-1/ e2x+C 24 1 2 1 4x D./x-/e +C 28
Dafna1 [17]
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C

Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
     u = x
     dv/dx = e^(2x)

By differentiating u, we get
     du/dx= 1
By integrating dv/dx= e^(2x), we have
     v =∫e^(2x) dx = (1/2)e^(2x)

Then we substitute these values to the integration by parts formula:
     ∫ u(dv/dx) dx = uv −∫ v(du/dx) dx 
     ∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
                          = (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
                          = (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.

Therefore, 
     ∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
7 0
4 years ago
What is 3x plus 4 equals 12
____ [38]

Answer:

3x + 4 = 12

Step-by-step explanation:

plus = +

equal =  =

but if you were looking for the answer to the equation

3x + 4 = 12

3x = 12 - 4    (the symbol changes bc i switched it to the other                        side)

3x = 8

x = 8/3

~batmans wife dun dun dun.....

5 0
3 years ago
Choose the triangle that seems to be congruent to the given one.
arsen [322]

AFB, the sides are similar

6 0
3 years ago
What time is 1 hour and 37 minutes before 3:13 P.M.?
AfilCa [17]
3:13 - 1:00 = 2:13

2:13 - 0:37 = 1:36

1:36 is your answer.

Glad I could help, and good luck!

AnonymousGiantsFan



3 0
3 years ago
Read 2 more answers
Thi sis the question
jek_recluse [69]

\text{Given that,}\\\\x^2 + \dfrac1{x^2} = 38\\\\\\(i)\\\\\left(x-\dfrac 1x \right)^2 = x^2 + \dfrac 1{x^2} - 2 \cdot x \cdot \dfrac 1x\\\\\\\implies \left(x-\dfrac 1x \right)^2 = 38 -2 = 36\\\\\implies x - \dfrac 1x = \pm\sqrt{36} = \pm 6 \\\\\\(ii)\\\\x^2 + \dfrac 1{x^2} = 38\\\\\\\implies \left(x^2 + \dfrac 1{x^2} \right)^2 = 38^2\\\\\\\implies x^4 + \dfrac 1{x^4} + 2\cdot x^2 \cdot \dfrac 1{x^2} = 1444\\\\\\\implies x^4 + \dfrac 1{x^4} + 2 = 1444\\\\\\

\implies x^4 +\dfrac 1{x^4} = 1444-2 = 1442

7 0
2 years ago
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