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saul85 [17]
3 years ago
5

There are 8 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being

the last​ stand-up comic of the evening. If this​ performer's request is​ granted, how many different ways are there to schedule the​ appearances?
Mathematics
1 answer:
artcher [175]3 years ago
7 0
Since there are 8 but the last comedian will always perform last the amount of comedians you have to take into account in 7. To calculate the amount of combinations use 7! which is 5040. So there are 5040 different ways the comedians could be scheduled.
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Select the correct answer from each drop-down menu. In the figure, line segment AB is parallel to line segment CD. The measure o
victus00 [196]
<h3>Answer:</h3>

∠C = 40°

∠D = 75°

<h3>Step-by-step explanation:</h3>

AB ║ CD, so AD and BC are transversals. The angle pairs (A, D) and (B, C) are "alternate interior angles", hence congruent.

∠C = ∠B = 40°

∠D = ∠A = 75°

3 0
3 years ago
In simplest radical form, what are the solutions to the quadratic equation 0 = –3x2 – 4x + 5?
JulsSmile [24]
- 3 x² - 4 x + 5 = 0
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4 0
3 years ago
Solve the system of equations 5x-2y=88 3x+4y=58 show all work
diamong [38]
The given equations are:

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Multiplying the 1st equation by 2, we get the new set of equations as:

10x - 4y = 176
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6 0
3 years ago
Read 2 more answers
What is the solution for -6(1-5v)=54 ?
snow_tiger [21]

Isolate the variable by dividing each side by the factors that don't contain the variable

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4 0
3 years ago
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Dmitry [639]

Answer:

Step-by-step explanation:

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45t = 30 × (1 - t)

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t = 2 /5 hour to drive to work at 45mph

Since ,  d = rt

d = 45 ×(2/5) = 18miles

8 0
3 years ago
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