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saul85 [17]
3 years ago
5

There are 8 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being

the last​ stand-up comic of the evening. If this​ performer's request is​ granted, how many different ways are there to schedule the​ appearances?
Mathematics
1 answer:
artcher [175]3 years ago
7 0
Since there are 8 but the last comedian will always perform last the amount of comedians you have to take into account in 7. To calculate the amount of combinations use 7! which is 5040. So there are 5040 different ways the comedians could be scheduled.
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wariber [46]

Answer:

233568

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233568

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sergejj [24]

Answer:

3.75

Step-by-step explanation:

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Furthermore, you multiply the dividend denominator by the divisor numerator to make a new denominator:

To make the answer to 3/4 divided by 1/5 in decimal form, you simply divide the numerator by the denominator from the fraction answer above:

15/4 = 3.75

The answer is rounded to the nearest four decimal points if necessary.

15/4 is an improper fraction and should be written as 3 3/4.

 

 

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