Question

Find the volume of a cone with base area 9π ft2 and a height equal to twice the radius.

Answer 1

Answer:

$18\pi$ ft cubed

Step-by-step explanation:

The volume of a cone is: $V=\frac{1}{3} \pi r^2h$ , where $\pi r^2$ is the base and h is the height.

In this case, we see that the base is: $\pi r^2=9\pi$. Solving for r, we see that the radius is $\sqrt{9} =3$.

The height is twice the radius, so h = 2 * 3 = 6. Now, we have all the necessary values that we can plug into the equation to get the volume:

$V=\frac{1}{3} *9\pi *6=18\pi$

Thus, the answer is $18\pi$ ft cubed.

Hope this helps!

Answer 2

Answer:

18π ft³

Step-by-step explanation:

Base area = pi × r² = 9pi

r² = 9

r = 3

h = 3 × 2 = 6

Volume = ⅓ × pi × r² × h

⅓ × 9pi × 6

18pi ft³