Answer:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
- d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
- After first dose residual drug amount is:
d= 500*0.045= 22.5 mg
- After second dose:
d= 22.5*2= 45 mg
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer:
The answer is D).
Step-by-step explanation:
I am assuming that you are talking about exponents and powers. So I assumed that:
A) was 4.325 * 10^-9,
B) was 4.325 * 10^-6,
C) was 4.325 * 10^6,
D) was 4.325 * 10^9
I just went for gusto, and multiplied/solved answer D), and it was correct. I just punched into calculator, and boom. 4,325,000,000. I hope this helps!
<h2>
<u>PLEASE MARK BRAINLIEST!</u></h2>
Divided 75000 by 10000 so it would be 7.5 square cm
F(x)=2ˣ
f(x)
(x,y)
(0,1)
(1,2)
(2,4)
(3,8)
(4,16)
(5,32)
(6,64)
(7,128)
(8,256)
(9,512)
(10,1024)
h(x)
(x,y)
(0,8)
(1,10)
(2,18)
(3,38)
(4,76)
(5,138)
(6,230)
(7,358)
(8,528)
(9,736)
(10,1018)
so somwehre between x=9 and x=10
hmm
f(9.5)=724.007
h(9.5)=874.875
go to 9.75
f(9.75)=944.609
h(9.75)=861.078
up
9.9
f(9.9)=955.426
h(9.9)=988.199
up
9.95
f(9.95)=989.119
h(9.95)=1003.02
up
9.99
f(9.99)=1016.93
h(9.99)=1014.99
a bit down
9.98
f(9.98)=1009.9
h(9.98)=1011.99
a bit up
9.985
f(9.985)=1013.41
h(9.985)=1013.49
pretty close, ya
so about at 9.985=x
if we graphed, we get that x=9.98512070914982..., so we are pretty close
Step-by-step explanation:
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