If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
10y + 20 is an equivalent expression
To solve this you would divide until you can’t. I recommend staying in whole numbers:) I always divide by twos because I think it’s more efficient! 4 divided by 2 is 2 and 30 divided by 2 is 15 sooo (2 hours to 15) hope this helped!
3/7
6 divided by 2 equals 3
14 divided by 2 equals 7
is 12.5 ok I think ,......................,,,,,,