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Diano4ka-milaya [45]
3 years ago
14

Two race cars,car x an y,are at the starting point of a two km track at the same time.car x and car y make one lap every 60 s an

d every 80 sec respectively.
How long, in minutes, will it take for the faster car to be 5 laps ahead of the slower car?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
4 0

Answer is attached.

Please check the image.

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6 0
3 years ago
Solve for z: -14z - -16z - -8z - 11z +7z = -12
Jet001 [13]
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8 0
3 years ago
Choose the appropriate pattern and use it to find the product: (p4−q4)(p4+q4).
sp2606 [1]

The expression can be solved by expanding the bracket and multiplying out the terms

(p^4-q^4)(p^4+q^4)\begin{gathered} =p^4(p^4+q^4)-q^4(p^4+q^4) \\ =p^8+p^4q^4-p^4q^4-q^8 \\ =p^8-q^8 \end{gathered}

Therefore, the expression can be simplified as;

p^8-q^8

Alternatively, using the theorem of difference of two squares, which is

a^2-b^2=(a-b)(a+b)

Hence,

p^8-q^8=(p^4)^2-(q^4)^2

7 0
1 year ago
Four students simplify the expression below: 6 + 4 x 10 ÷ 2 Anshu's solution is 25 , David's solution is 46 , Jimmy's solution i
Mrac [35]

Answer:

Jimmy; 26

Step-by-step explanation:

PEMDAS

Parentheses Exponents Multiplication Division Addition Subtraction

6 + 4 * 10 / 2 = 6 + 40 / 2

6 + 40 / 2 = 6 + 20

6 + 20 = 26

26

7 0
2 years ago
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