Two race cars,car x an y,are at the starting point of a two km track at the same time.car x and car y make one lap every 60 s an
d every 80 sec respectively.
How long, in minutes, will it take for the faster car to be 5 laps ahead of the slower car?
How long, in minutes, will it take for the faster car to be 5 laps ahead of the slower car?
1 answer:
You might be interested in
The value of expression is 7.
<h3>What is expression?</h3>An expression is a combination of numbers, variables, functions (such as addition, subtraction, multiplication or division etc.)
Given:
Now, using property of log
a log b
So,
= 7 log 10
As log 10 = 1
= 7 (1)
= 7
Learn more expression here:
#SPJ1