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3 years ago

Divide 3 8 ÷ 2 3 and express the answer in simplest terms.

Mathematics

1 answer:

sweet-ann [11.9K]3 years ago

5 0

Answer:

1 $\frac{15}{23}$

Step-by-step explanation:

38 ÷ 23 = $\frac{38}{23}$

Since 38 is bigger than 23, you can pull a $\frac{23}{23}$ from $\frac{38}{23}$ .

$\frac{38}{23}$ = $\frac{23}{23}$ + $\frac{15}{23}$

$\frac{23}{23}$ is basically one whole, so you can put the answer as a mixed number.

$\frac{23}{23}$ + $\frac{15}{23}$ = 1 + $\frac{15}{23}$

= 1 $\frac{15}{23}$

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Leno4ka [110]

Answer:

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3 years ago

Suppose that bugs are present in 1% of all computer programs. A computer de-bugging program detects an actual bug with probabili

lawyer [7]

Answer:

(i) The probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii) The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

Step-by-step explanation:

Denote the events as follows:

B = bugs are present in a computer program.

D = a de-bugging program detects the bug.

The information provided is:

$P(B) =0.01\\P(D|B)=0.99\\P(D|B^{c})=0.02$

(i)

The probability that there is a bug in the program given that the de-bugging program has detected the bug is, P (B | D).

The Bayes' theorem states that the conditional probability of an event E given that another event X has already occurred is:

$P(E|X)=\frac{P(X|E)P(E)}{P(X|E)P(E)+P(X|E^{c})P(E^{c})}$

Use the Bayes' theorem to compute the value of P (B | D) as follows:

$P(B|D)=\frac{P(D|B)P(B)}{P(D|B)P(B)+P(D|B^{c})P(B^{c})}=\frac{(0.99\times 0.01)}{(0.99\times 0.01)+(0.02\times (1-0.01))}=0.3333$

Thus, the probability that there is a bug in the program given that the de-bugging program has detected the bug is 0.3333.

(ii)

The probability that a bug is actually present given that the de-bugging program claims that bug is present is:

P (B|D) = 0.3333

Now it is provided that two tests are performed on the program A.

Both the test are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is:

P (Bugs are actually present | Detects on both test) = P (B|D) × P (B|D)

$=0.3333\times 0.3333\\=0.11108889\\\approx 0.1111$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on both the first and second tests is 0.1111.

(iii)

Now it is provided that three tests are performed on the program A.

All the three tests are independent of each other.

The probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is:

P (Bugs are actually present | Detects on all 3 test)

= P (B|D) × P (B|D) × P (B|D)

$=0.3333\times 0.3333\times 0.3333\\=0.037025927037\\\approx 0.037$

Thus, the probability that the bug is actually present given that the de-bugging program claims that bugs are present on all three tests is 0.037.

4 0

3 years ago

122.55 is 47 1/2 of what number???

klemol [59]

Answer:

2.58

Step-by-step explanation:

47 1/2=95/2

122.55/(95/2)=(122.55/1)(2/95)=245.1/95=2.58

6 0

3 years ago

Help question below please and thank you i will give brainliest

vodomira [7]

Answer: angle V = 41 degrees (choice B)

======================================================

Explanation:

We're told that RS = ST = RT. This means triangle RST has all three sides equal to one another. This triangle is equilateral. Each interior angle is 60 degrees. This is because each angle is y, and y+y+y = 180.

Since each angle of triangle RST is 60 degrees, this means angle STR is 60 degrees.

Let z be the measure of angle UTV. Note how

(angleSTR)+(angleUTV) = 180

60+z = 180

z = 180-60

z = 120

Making angle UTV to be 120 degrees

------------------------------------

Now we can focus on triangle UTV since we have expressions for each interior angle

U = 4x-9
T = 120
V = 5x+6

Add up those angles, set the sum equal to 180, solve for x

U+T+V = 180

(4x-9)+(120)+(5x+6) = 180

9x+117 = 180

9x = 180-117

9x = 63

x = 63/9

x = 7

Use that x value to find the missing angle measures

angle U = 4x-9 = 4*7-9 = 28-9 = 19 degrees

angle V = 5x+6 = 5*7+6 = 35+6 = 41 degrees

Note how

U+T+V = 19+120+41 = 180

which helps confirm our answer.

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3 years ago

Read 2 more answers

State if the pair of triangles are similiar. pls help

sattari [20]

Answer:

No, they are not similar

Step-by-step explanation:

25/107 = 16/88

Cross multiply

25 * 88 = 107 * 16

2200 = 1712

No, they are not similar

6 0

3 years ago