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2 years ago

6

Jonah wrote a 5-digit number on a piece of paper. He gave his friend Marney these clues to find the number. A. the 4 is in the p

lace that is ten times greater than the place where the 4 is. B. the 2 is in the place that is one hundred times less than the place where the 5 is. C. the 6 is in the place that is ten times less than the place where the 2 is. D. the 1 is in the place that is ten times greater than the place where the 5 is. what is the number?

2 answers:

Whitepunk [10]2 years ago

8 0

15426 is the answer it shall be

Nuetrik [128]2 years ago

6 0

Answer:

The required number is 15426 satisfying all conditions.

Step-by-step explanation:

Given : Jonah wrote a 5-digit number on a piece of paper. He gave his friend Marney these clues to find the number.

To find : What is the number ?

Solution :

5-digit number,

Ten Th. Thousand Hundred Tens ones

Examine the clues

A. The 4 is in the place that is ten times greater than the place where the 4 is

B. The 2 is in the place that is one hundred times less than the place where the 5 is i.e. 5 followed by something then followed by 2.

C. The 6 is in the place that is ten times less than the place where the 2 is i.e. 6 follows by 2.

D. The 1 is in the place that is ten times greater than the place where the 5 is i.e. 1 is before 5

So, From clue B,C,D the number is 15_26.

The space left is 4.

Therefore, The required number is 15426 satisfying all conditions.

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A company has two manufacturing plants with daily production levels of 5x+17 and 3y-4,respectively.

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Complete question :

A company has two manufacturing plants with daily production levels of 5x + 11 items and 2x - 3 items, respectively, where x represents a minimum quantity. The first plant produces how many more items daily than the second plant?

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Step-by-step explanation:

Given that:

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Open the bracket :

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riadik2000 [5.3K]

Answer:

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2 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

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Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

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(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

$P(X$

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

$P(X$

Take natural log on both sides.

$ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30$

Thus, the value of x is 30.

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3 years ago