Answer:
44
Step-by-step explanation:
The LCD of 3 and 4 is 12. To make 4 into 12, we multiply it by three, so 3 would also have to be multiply by 3, turning 3/4 into 9/12.
The same thing applies to 1/3, only it needs to be multiplied by 4. So it would become 4/12
9/12 - 4/12 = 5/12
Answer:
- P(Yellow)=0.25
- P(Not Red)=0.65
Step-by-step explanation:
P(Red)=0.35
P(Green)=0.4
(a)Since there are three colours inside the bag
P(Red)+P(Green)+P(Yellow)=1
0.35+0.4+P(Yellow)=1
P(Yellow)=1-(0.35+0.4)
P(Yellow)=0.25
(b) In probability, the sum of an event and its complement is 1.
Therefore:
P(Red)+P(Not Red)=1
0.35+P(Not Red)=1
P(Not Red)=1-0.35
P(Not Red)=0.65
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
Answer:55
Step-by-step explanation:
55
