Answer is x= 3 or x= -2
x(x+2) -3 (x+2) = 0
(x+2) (x-3) =0
x+2=0
x-3=0
so..
x=-2
x=3
hope this helped a bit good luck :)
Answer:
-1
Step-by-step explanation:
The expression evaluates to the indeterminate form -∞/∞, so L'Hopital's rule is appropriately applied. We assume this is the common log.
d(log(x))/dx = 1/(x·ln(10))
d(log(cot(x)))/dx = 1/(cot(x)·ln(10)·(-csc²(x)) = -1/(sin(x)·cos(x)·ln(10))
Then the ratio of these derivatives is ...
lim = -sin(x)cos(x)·ln(10)/(x·ln(10)) = -sin(x)cos(x)/x
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At x=0, this has the indeterminate form 0/0, so L'Hopital's rule can be applied again.
d(-sin(x)cos(x))/dx = -cos(2x)
dx/dx = 1
so the limit is ...
lim = -cos(2x)/1
lim = -1 when evaluated at x=0.
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I find it useful to use a graphing calculator to give an estimate of the limit of an indeterminate form.
A. 0.25
B. 0.6
C. 0.721
D. 0.07
E. 0.095
F. .0066
When you convert percentages into decimals always move the . two spaces to the left.
3(-1.5)-5=
-4.5-5=
-9.5
3(2)-5=
6-5=
1
3(4)-5=
12-5=
7
{f(-1.5),f(2),f(4)} = {-9.5,1,7}
..... 40.5 ...............