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3 years ago

12

The sum of the numbers as the product of their GCF and other sum so what is 32 plus 20???

1 answer:

densk [106]3 years ago

4 0

I dont quite undeerstand but the gcf for both are..., if that helps is 4 because
30:2*2*2*2*2
22:2*2 5

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Can someone help me with this

spin [16.1K]

Answer:

Options A, C, and F

Step-by-step explanation:

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3 years ago

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Help please soon !!!!!!

stepan [7]

75.25x + 3604 = 300.50x
300.50x - 75.25x = 3604
225.25x = 3604
x = 16
Both companies charged the same at 16 tons
first answer 16 tons
--------------------
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second answer is $4,808

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4 years ago

Variable y varies directly with variable x, and y = 5 when x = 8.

qaws [65]

Y = kx

Plug in what we know:

5 = k(8)

5 = 8k

Divide 8 to both sides:

k = 0.625

Plug this back into the equation along with y = 15:

y = kx

15 = 0.625x

Divide 0.625 to both sides:

x = 24

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3 years ago

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What is the area, in square meters, of the rhombus above?

Sidana [21]

Answer:

C

Step-by-step explanation:

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3 years ago

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A pharmacist receives a shipment of 22 bottles of a drug and has 3 of the bottles tested. If 5 of the 22 bottles are contaminate

Norma-Jean [14]

Answer:

There is a 44.16% probability that exactly 1 of the tested bottles is contaminated.

Step-by-step explanation:

$C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this problem, we have that:

Total number of combinations:

$C_{22,3} = \frac{22!}{3!(18)!} = 1540$

Desired combinations:

It is 1 one 5(contamined) and 2 of 17(non contamined). So:

$C_{5,1}*C_{17,2} = 5*17*8 = 680$

What is the probability that exactly 1 of the tested bottles is contaminated?

$P = \frac{680}{1540} = 0.4416$

There is a 44.16% probability that exactly 1 of the tested bottles is contaminated.

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3 years ago