If Sa=2πrh+2π
v=π
then the surface area is π
and volume is
(rh-2h)/2r.
Given Sa=2πrh+2π
=π
.
We have to find surface area and volume from the given expression.
Volume is basically amount of substance a container can hold in its capacity.
First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.
2πrh+2π
v=π
h
Keeping the term containing v at left side and take all other to right side.
2π
v=π
-2πrh
v=(π
h-2πrh)/2π
v=π
/2π
-2πrh/2π
v=h/2-h/r
v=h(r-2)/2r
Put the value of v in Sa=2πrh+2π
Sa=2πrh+2π
*h(r-2)/2r
=2πrh+2πrh(r-2)/2
=2πrh+πrh(r-2)
=2πrh+π
h-2πrh
=π
h
Hence surface area is π
h and volume is h(r-2)/2.
Learn more about surface area at brainly.com/question/16519513
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Answer:
243
Step-by-step explanation:
3x3=9
9x3=27
27x3=81
81x3=243
<span>2/3x -4=-2
-------------------
Add 4 to each side
</span><span>2/3x-4+4</span>=-<span>2+<span>4
2/3x = 2
-----------------------------
Multiply each side by 3/2
(3/2) * (2/3x) = (3/2) * (2)
x = 3</span></span>
Answer:
Width = 18, height = 3
Or
Width = 6, height = 9
Step-by-step explanation:
Complete question
( A piece of sheet metal 24 inches wide is bent to form a gutter as shown in the picture below, if the cross sectional area is 54 square inches, find the depth of the gutter).
X = width, Y = height
X - 2y = 24........ equation i
X = 24 - 2y.......... equation ii
Area = xy
54 = xy........ equation iii
Put equation ii into equation iii
54 = (24 - 2y) * y
54 = 24y - 2y²
2y² - 24y + 54 = 0........ equation iv
Solving equation iv using quadratic methods,
Factors = (y-3), (y-9)
(Y-3)(y-9) = 0
y = 3 or y = 9
Substitute y = 3 or y = 9 into equation ii
X = 24 -2(3) = 18 or x = 24 - 2(9) = 6
If Width = 18, height = 3
Or
Width = 6, height = 9
Basically find the prime numbers that multiply to make that number or the base parts so
90=2 times 45
45=3 times 15
15=3 times 5
prime factor=2 times 3 times 3 times 5