Question

If anyone can help with either one that’d be great

Answer 1

4.  Solve

$1430 = 0.55t^2 + 550$

$1430 - 550 =880 = 0.55t^2$

$880/0.55 = 1600 = t^2$

$t= \pm \sqrt{1600} = \pm 40$

On the positive answer makes sense.

Answer: Month 40

5. The throw ends when the height is zero (I guess we're ignoring rolling).

$0 = -0.02x^2 + x + 6$

$x = \dfrac{-1 \pm \sqrt{1^2 - 4(6)(-0.02)}}{2(-0.02)}$

Only the negative sign for the plus/minus will give a sensible, positive answer:

$x = \dfrac{-1 - \sqrt{1^2 - 4(6)(-0.02)}}{2(-0.02)} = 55.4138$

Answer: 55.4 feet