Answer:
79853709 with the exponent of 94
Step-by-step explanation:
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
Answer:
25000076
Step-by-step explanation:
Hope this helps! :)
Answer:
130
Step-by-step explanation:
4*5+10(11)
20+110
130
Enjoy!
