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weeeeeb [17]
3 years ago
12

Lcm and gcf of 27 and 45

Mathematics
1 answer:
miss Akunina [59]3 years ago
5 0
Gcf: 9

27: 1, 3, 9, 27
45: 1, 3, 5, 9, 15, 45

lcm: 135

27, 54, 81, 108, 135,

45, 90, 135,
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Simplify the expressions. Show your work.
Hunter-Best [27]
7) Use distributive property
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5 0
3 years ago
Jack has a bag full of marbles. In the bag, there are 5 green marbles, 4 red marbles, and 6 blue marbles. Jack takes one marble
soldier1979 [14.2K]

Answer:

0

Step-by-step explanation:

Jack Bag Full of Marbles:

5 Green Marbles

4 Red Marbles

6 Blue Marbles

Jack takes one marble and then does not replace the marble in the bag.

Question:

What is the probability of grabbing a white marble on the first pull?

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We Know that Jack have Green, Red, and Blue Marbles..

And It has no white Marbles.

Hence, the answer is 0.

[RevyBreeze]

4 0
2 years ago
Please go through step by step so I can also learn the correct way. Will thank the person who goes step by step
juin [17]

Answer:

5.848 in

Step-by-step explanation:

Divide the piece of cardboard into nine equal squares of side z.

The centre square is the base of the cube.

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The cube must have a volume of 200 in³.

    V = z³

200 = z³

    z = \sqrt[3]{200}

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8 0
3 years ago
Super sports is offering a 20% discount on each pair of shoes.which originally priced $72.50. A 6.5% sales tax will be applied t
dlinn [17]
20% discount makes the price $58. Sales tax brings this to $61.77.
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5 0
3 years ago
Read 2 more answers
I need help ASAP! It's urgent.. PLISSSSS​
natali 33 [55]

Answer:

a) 6 mins

b) 70km/h

c) t= 45

Step-by-step explanation:

a) The bus stops from t=10 to t=16 minutes since the distance the busvtravelled remained constant at 15km

Duration

= 16 -10

= 6 minutes

b) Average speed

= total distance ÷ total time

Total time

= 24min

= (24÷60) hr

= 0.4 h

Average speed

= 28 ÷0.4

= 70 km/h

c) Average speed= total distance/ total time

Average speed

= 80km/h

= (80÷60) km/min

= 1⅓ km/min

1⅓= 28 ÷(t -24)

<em>since</em><em> </em><em>duration</em><em> </em><em>for</em><em> </em><em>return</em><em> </em><em>journey</em><em> </em><em>is</em><em> </em><em>from</em><em> </em><em>t</em><em>=</em><em>2</em><em>4</em><em> </em><em>mins</em><em> </em><em>to</em><em> </em><em>t</em><em> </em><em>mins</em><em>.</em>

\frac{4}{3}(t -24)= 28

\frac{4}{3}t - 32= 28

\frac{4}{3}t= 32 +28

\frac{4}{3}t= 60

t= 6 0\div  \frac{4}{3}

t= 45

*Here, I assume that this is a displacement- time graph, so the distance shown is the distance of the bus from the starting point because technically if it is a distance-time graph, the distance would still increase as the bus travels the 'return journey'.

Thus, distance is decreasing after t=24 and reaches zero at time= t mins so that is the return journey. (because when the bus returns back to starting point, displacement/ distance from starting point= 0km)

5 0
3 years ago
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