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lions [1.4K]
3 years ago
7

Pleas help! I do not understand.

Mathematics
1 answer:
castortr0y [4]3 years ago
7 0

Distance between 2 points formula:

d = √[(x1 - x2)^2 + (y1 - y2)^2]

Plug in

d = √[(-4√2 + √32)^2 + (-√12 - 2√3)^2]

d = √[(-4√2 + 4√2)^2 + (-2√3 - 2√3)^2]

d = √[0 + (-4√3)^2]

d = √(16 * 3)

d = 4√3

Answer

Last one

4√3

 

​

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What precent of 95 is 60.8​
dezoksy [38]

60.8 is 64% of 95.

Step-by-step explanation:

Given number is;

95

We have to find at what percent, the value is 60.8

Let x be the percent.

Therefore;

x% of 95 = 60.8

\frac{95x}{100}=60.8 \\0.95x=60.8

Dividing both sides by 0.95

\frac{0.95x}{0.95}=\frac{60.8}{0.95}\\x=64

60.8 is 64% of 95.

Keywords: percent, division

Learn more about division at:

  • brainly.com/question/10764770
  • brainly.com/question/1087090

#LearnwithBrainly

5 0
3 years ago
The perimeter of a triangle is 19z-7. One side is 5z-9 and one side is 8z+3. What is the remaining side ?
insens350 [35]
19z-7 - ( 5z-9 + <span>8z+3)
= 19z - 7 - (13z - 6)
= 19z - 7 - 13z + 6
= 6z - 1

answer
remaining side = </span> 6z - 1
3 0
2 years ago
19 is 20%of what number
zloy xaker [14]

Answer:

19 is 20% of 95.

Step-by-step explanation:

6 0
2 years ago
A metal worker has several 1-kilogram bars of a metal alloy that contain 23% copper and several 1-kilogram bars that contain 79%
astraxan [27]

Answer:

30 each of 23% bars and 18 each of 79% bars

Step-by-step explanation:

If x is the number of 1 kg 23% copper bars, and y is the number of 1 kg 79% copper bars, then:

x + y = 48

0.23x + 0.79y = 0.44(48)

Substituting and solving:

0.23x + 0.79(48-x) = 0.44(48)

0.23x + 37.92 - 0.79x = 21.12

16.8 = 0.56x

x = 30

y = 48 - x

y = 18

You need 30 each of 23% bars and 18 each of 79% bars.

4 0
3 years ago
convert the following logarithmic equation to the equivalent exponential equation. Use the caret (^) to enter exponents. y=ln x
GarryVolchara [31]
1. To solve this problem, you need to remember that an exponential function has the following form:
 
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</span> 
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5 0
3 years ago
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