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Tema [17]
3 years ago
9

What is the justification for the first step in proving the formula for factoring the sum of cubes?

Mathematics
1 answer:
Anna11 [10]3 years ago
5 0

Explanation:

The formula isnt correctly written, it should state:

a^3+b^3 = (a+b)(a^2-ab+b^2)

You have to start from (a+b)(a^2-ab+b^2)  and end in a³+b³. On your first step, you need to use the distributive property.

(a+b)(a^2-ab+b^2) = a*(a^2-ab+b^2) + b*(a^2-ab+b^2)

This is equal to

a*a^2-a*(ab) + a*b^2 + b*a^2-b*(ab) + b*b^2 = a^3 - a^2b + ab^2 +ba^2 -b^2a +b^3

Note that the second term, -a²b, is cancelled by the fourth term, ba², and the third term, ab², is cancelled by the fifht term, -b²a. Therefore, the final result is a³+b³, as we wanted to.

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What is 10 squared plus b squared equals 22 squared
klio [65]
I'm pretty sure you are asking for the value of b. Let's actually write it and then solve it:
10^2 + b^2 = 22^2

Solving for b yields:
b = \sqrt{22^2-10^2} = \sqrt{484-100} = \sqrt{384} = 19.59

So, b = 19.59. If you want the answer in simplified radical form, we can also do that:
\sqrt{384} =  \sqrt{16*24} = 4 \sqrt{24} = 4 \sqrt{4*6} = 8 \sqrt{6}

So, b = 8√6 = 19.59
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Step-by-step explanation:

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