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ivann1987 [24]
3 years ago
6

PLZZZZZZZZZZZZZZZZZ HELP ASAP

Mathematics
1 answer:
kondaur [170]3 years ago
8 0

Answer:

B

Step-by-step explanation:

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Mrs. McCormick asked students to track the number of times they referred to their planner to check for assignment details during
borishaifa [10]

Answer:

B

Step-by-step explanation:

the answer is b because the they are only 5 numbers of student that check in for assignment details

6 0
2 years ago
Solve the equation for z^3-z^2-12z=0<br><br> The solutions are z=?, z=?, and z=?
Assoli18 [71]

Answer:

z is equal to 0,4, and -3

Step-by-step explanation:

3 0
3 years ago
2.1(0.2x-1.4)=1.3(0.4x—3.5)<br><br> Pls help.
Tresset [83]

Answer:

x=161/10 =16.100

Step-by-step explanation:

Combine Like Terms

3 0
3 years ago
Read 2 more answers
Use Laplace transform methods to solve the differential equation: The initial conditions are f(0) = 0 and <img src="https://tex.
Llana [10]

Answer:

Step-by-step explanation:

\frac{d^2 y}{dt^2} +12\frac{dy}{dt} +32y = 10e^{-2t} where f(x) is replaced by y

Take Laplace on both sides

s^2 Y -s(0)-0 +12s Y-0+32Y = \frac{10}{s+2} \\Y(s^2+12s+32) =  \frac{10}{s+2}\\Y =  \frac{10}{(s+2)(s+4)(s+8)}

We can resolve into partial fraction to get Y = L(y)

Let this equals

\frac{A}{s+2} +\frac{B}{s+4} +\frac{C}{s+8} \\10 = A(s+4)(s+8) + B(s+2)(s+8) +Cs+4)(s+2) \\

Solving we get

s=-9

24C = 10 or C =5/12

s=-2:  A=10/12=5/6

s=-4: B = -5/4

Taking inverse Laplace

y(t) = \frac{-5e^{-4t} }{4} + \frac{5e^{-8t} }{12} +\frac{-5e^{-2t} }{6}

6 0
3 years ago
Write a reciprocal function with asymptotes x=4 and y=-9.
gayaneshka [121]
Attached the solution and work.

5 0
3 years ago
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