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Darina [25.2K]
3 years ago
6

How many cm are in 6.9km6.9cm690,000cm6,900cm​

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
6 0

Answer:

690,000 thanks for asking

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What is 2/8+1/6 in the simplest form.
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Answer:

20/48

Step-by-step explanation:

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In the equation Q – 12 = 89, what is the value of Q
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The answer is 101 because you add 89 and 12

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Using the following triangle, what is the cosine of angle B?
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Answer:

  cos(B) = a/c

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you that ...

  Cos = Adjacent/Hypotenuse

The leg adjacent to angle B is "a". The hypotenuse is "c", so the desired cosine is ...

  cos(B) = adjacent/hypotenuse = a/c

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Brahmagupta solved a quadratic equation of the form ax2 + bx = c using the formula x=V
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2nd box- -8

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In triangle KLM, if K is congruent to L, KL = 9x - 40, LM = 7x - 37, & KM = 3x + 23, find x & the measure of each angle.
Dennis_Churaev [7]

Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°

<u>Step-by-step explanation:</u>

Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL

 KM ≅ LM

3x + 23 = 7x - 37

       23 = 4x - 37

       60 = 4x

        15 = x

KM = LM = 3x + 23

               = 3(15) + 23

               = 45 + 23

               = 68

KL = 9x - 40

    = 9(15) - 40

    = 135 - 40

    = 95

Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.

  • Since N is the midpoint of KL and KL = 95, then NL = 47.5
  • Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse

Use trig to solve for ∠L (which equals ∠K):

cos ∠L = \frac{adjacent}{hypotenuse}

cos ∠L = \frac{47.5}{68}

      ∠L = cos⁻¹ (\frac{47.5}{68})

      ∠L = 45.7  

Triangle sum Theorem:

∠K + ∠L + ∠M = 180°    

45.7 + 45.7 + ∠M = 180

       91.4     + ∠M = 180

                      ∠M = 88.6

       

7 0
3 years ago
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