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Mekhanik [1.2K]
3 years ago
12

what if your making a 68 in a class and then you make a 50 on a test and its worth 50% of your grade what are you making then in

your class this is a example of somebody in a class i know
Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0
You'd have a 59 in the class
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What type of symmetry is shown in this picture (point, line, or rotational)? Explain your answer and identify the line of symmet
ludmilkaskok [199]

Answer:

  symmetry about the y-axis is shown

Step-by-step explanation:

Points on the right of the line of symmetry (x=0, the y-axis) are the same distance from that line as the corresponding points on the left. (That is what makes it a line of symmetry.)

There is no point of rotation that will map one figure to the other after rotation, hence no point or rotational symmetry.

8 0
3 years ago
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According to one cosmological theory, there were equal amounts of the two uranium isotopes 235U and 238U at the creation of the
FromTheMoon [43]

Answer:

6 billion years.

Step-by-step explanation:

According to the decay law, the amount of the radioactive substance that decays is proportional to each instant to the amount of substance present. Let P(t) be the amount of ^{235}U and Q(t) be the amount of ^{238}U after t years.

Then, we obtain two differential equations

                               \frac{dP}{dt} = -k_1P \quad \frac{dQ}{dt} = -k_2Q

where k_1 and k_2 are proportionality constants and the minus signs denotes decay.

Rearranging terms in the equations gives

                             \frac{dP}{P} = -k_1dt \quad \frac{dQ}{Q} = -k_2dt

Now, the variables are separated, P and Q appear only on the left, and t appears only on the right, so that we can integrate both sides.

                         \int \frac{dP}{P} = -k_1 \int dt \quad \int \frac{dQ}{Q} = -k_2\int dt

which yields

                      \ln |P| = -k_1t + c_1 \quad \ln |Q| = -k_2t + c_2,

where c_1 and c_2 are constants of integration.

By taking exponents, we obtain

                     e^{\ln |P|} = e^{-k_1t + c_1}  \quad e^{\ln |Q|} = e^{-k_12t + c_2}

Hence,

                            P  = C_1e^{-k_1t} \quad Q  = C_2e^{-k_2t},

where C_1 := \pm e^{c_1} and C_2 := \pm e^{c_2}.

Since the amounts of the uranium isotopes were the same initially, we obtain the initial condition

                                 P(0) = Q(0) = C

Substituting 0 for P in the general solution gives

                         C = P(0) = C_1 e^0 \implies C= C_1

Similarly, we obtain C = C_2 and

                                P  = Ce^{-k_1t} \quad Q  = Ce^{-k_2t}

The relation between the decay constant k and the half-life is given by

                                            \tau = \frac{\ln 2}{k}

We can use this fact to determine the numeric values of the decay constants k_1 and k_2. Thus,

                     4.51 \times 10^9 = \frac{\ln 2}{k_1} \implies k_1 = \frac{\ln 2}{4.51 \times 10^9}

and

                     7.10 \times 10^8 = \frac{\ln 2}{k_2} \implies k_2 = \frac{\ln 2}{7.10 \times 10^8}

Therefore,

                              P  = Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} \quad Q  = Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}

We have that

                                          \frac{P(t)}{Q(t)} = 137.7

Hence,

                                   \frac{Ce^{-\frac{\ln 2}{4.51 \times 10^9}t} }{Ce^{-k_2 = \frac{\ln 2}{7.10 \times 10^8}t}} = 137.7

Solving for t yields t \approx 6 \times 10^9, which means that the age of the  universe is about 6 billion years.

5 0
3 years ago
Two acute triangles are similar. Which of the following must the similar triangle have?
abruzzese [7]
B is the only one that makes sense if you break them each down. An Acute doesnt have every Pair of angles congruent, the don't have to have proportional side lengths, and it can't have a right angle or it would be a right triangle.
7 0
3 years ago
Read 2 more answers
Algebra 1 :
victus00 [196]

What we have been given here are two points.

f(3) = -4 is the same as (3, -4)

f(2) = 6 is the same as (2, 6)

We can then use these two points to find the equation of a line.

Step 1: Find the slope

Slope Formula: (y2 - y1) / (x2 - x1)

Slope = (6 - - 4) / (2 - 3) = (10) / (-1) = -10

Step 2: Find the y-intercept

To find the y-intercept, we'll take our slope and one of our points and plug them into slope-intercept form, then solve for b.

Slope-Intercept Form: y = mx + b

Point = (2, 6)

6 = 2(-10) + b

6 = -20 + b

b = 26

Step 3: Create the equation of the line

Now that we have the slope and y-intercept, all that's left to do is plug both of those values into slope-intercept form.

y = -10x + 26

Answer: y = -10x + 26

Hope this helps!

3 0
2 years ago
6x - 5 = 5x + 3<br> If you get it right you get brainest
matrenka [14]

Answer:

x = 8

Step-by-step explanation:

6x - 5 = 5x + 3

6x - 5x = 3 + 5 (combining like-terms)

x = 8

Hope this helps!

4 0
3 years ago
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