All categories

3 years ago

The seventh term of the sequence -2, -6, -10, -14, ... is _____. -26 -24 -22 -20

1 answer:

7 0

We'll it keeps on subtracting by 4 to get each number.

-2,-6,-10,-14,-18,-22,-26.

Negative 26 is your answer. Hope this helped!

You might be interested in

Solve the following system of equations using substitution. 4x + 2y = 12 x = y + 3

BigorU [14]

Answer:

x = 3

y = 0

Step-by-step explanation:

The method of substitution is when one solves an equation for one of the variables, and then substitutes the expression into the other equation. After doing so, one will solve the other equation for the remaining variable and then backsolve for the first variable.

4x + 2y = 12

x = y + 3

The second equation is already sovled for parameter (x), subttiute this into the other equation,

4(y + 3) + 2y = 12

Distribute,

4y + 12 + 2y = 12

Simplify,

6y + 12 = 12

Inverse operations,

6y + 12 = 12

-12

6y = 0

y = 0

Backsolve for (x), substitute the value of (y) into the equation for (x) and solve,

x = y + 3

x = 0 + 3

x = 3

4 0

3 years ago

Read 2 more answers

Nina and Cindy went to the early show. Tickets were $3.00 each. They shared a jumbo popcorn for $4.50 and each girl bought a sma

AlexFokin [52]

Answer:

$18.50

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Please help ! :0 -17 = 2y/3 + 3y/4

VashaNatasha [74]

Hi,

Equation;

$- 17 = \frac{2y}{3} + \frac{3y}{4}$

Solving:

$- 17 = \frac{2y}{3} + \frac{3y}{4} \: \: \: | \div 12 \\ - 204 = 8y + 9y \\ - 204 = 17y \\ 17y = - 204 \: \: \: | \div 17 \\ \\ y = - 12 \: \: \: \: \: \: \: \: (result)$

Hope this helps.
r3t40

6 0

3 years ago

Mark the statement either true (in all cases) or false (for at least one example). If false, construct a specific example to sho

LUCKY_DIMON [66]

Answer with Step-by-step explanation:

We are given that $v_1,v_2,..,v_4$ are in $R^4$ and $v_1,v_2,v_3$ is linearly dependent then {v_1,v_2,v_3,v_4}[/tex] is also linearly dependent.

We have to find that given statement is true or false.

Dependent vectors:Dependent vectors are those vectors in which atleast one vector is a linear combination of other given vectors.

Or If we have vectors $x_1,x_2,....x_n$

Then their linear combination

$a_1x_1+a_2x_2+.....+a_nx_n=0$

There exist at least one scalar which is not zero.

If $v_1,v_2,v_3$ are dependent vectors then

$a_1v_1+a_2v_2+a_3v_3=0$ for scalars $a_1,a_2,a_3$

Then , by definition of dependent vectors

There exist a vector which is not equal to zero

If vector $v_3$ is a linear combination of $v_1\;and \;v_2$ , So at least one of vectors in the set is a linear combination of others and the set is linearly dependent.