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ICE Princess25 [194]
3 years ago
8

An electron is released from rest in a weak electric field given by vector E = -1.30 10-10 N/C ĵ. After the electron has travel

ed a vertical distance of 1.6 µm, what is its speed? (Do not neglect the gravitational force on the electron.)
Physics
1 answer:
Murljashka [212]3 years ago
4 0

Answer:

v =  6.45 10⁻³ m / s

Explanation:

Electric force is

               F = q E

Where q is the charge and E is the electric field

Let's use Newton's second law to find acceleration

                F- W = m a

               a = F / m - g

               a = q / m E  g

Let's calculate

               a = -1.6 10⁻¹⁹ / 9.1 10⁻³¹ (-1.30 10⁻¹⁰) - 9.8

              a = 0.228 10² -9.8

              a=  13.0 m / s²

Now we can use kinematics, knowing that the resting parts electrons

              v² = v₀² + 2 a y

              v =√ (0 + 2 13.0 1.6 10⁻⁶)

            v =  6.45 10⁻³ m / s

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Sedbober [7]

Answer:

e) 120m/s

Explanation:

When the ball reaches its highest point, its velocity becomes zero, meaning

v_0-gt = 0.

where v_0 is the initial velocity.

Solving for t we get

t = \dfrac{v_0}{g}

which is the time it takes the ball to reach the highest point.

Now, after the ball has reached its highest point, it turns around and falls downwards. After time t_0 since it had reached the highest point, the ball has traveled downwards and the velocity v_f it has gained is

v_f = gt_0,

and we are told that this is twice the initial velocity v_0; therefore,

v_f = 2v_0  = gt_0

which gives

t_0 = \dfrac{2v_0}{g}.

Thus, the total time taken to reach velocity 2v_0 is

t_{tot} = t+t_0 = \dfrac{v_0}{g}+\dfrac{2v_0}{g}

t_{tot} = \dfrac{3v_0}{g}.

This t_{tot}, we are told, is 36 seconds; therefore,

36= \dfrac{3v_0}{g},

and solving for v_0 we get:

v_0 = \dfrac{36g}{3}

v_0 = \dfrac{36s(10m/s^2)}{3}

\boxed{v_0 = 120m/s}

which from the options given is choice e.

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3 years ago
Which of two factors influence the weight of an object due to gravitational pull?
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a skydiver jumped out of a plane and fell 9 miles to the ground. his average speed while falling was 174 miles/hour. how much ti
shutvik [7]

Answer:

t = 0.051 seconds

Explanation:

Given that,

A skydiver jumped out of a plane and fell 9 miles to the ground. It means 9 miles is the distance covered.

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We need to find the time for which he dive last. It means t is the time taken. Total distance covered divided by time taken is called average speed. So,

v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{9}{174}\\\\t=0.051\ s

So, a skydiver dive for 0.051 seconds.

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