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3 years ago

I need someone that has a course hero subscription to help me I need all the pages

Physics

1 answer:

SVETLANKA909090 [29]3 years ago

8 0

Answer:

So what's the answer???

Explanation:

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Mae prefers to complete graphs or charts to show the information she has learned. What kind of learner is Mae likely to be?

yan [13]

Answer:

Prob. D

Explanation:

I am also a Visual Learner.

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3 years ago

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Question 4

mamaluj [8]

Answer:

What is an electromagnetic wave

Explanation:

Electromagnetic radiation is also more commonly known as light, light travels in waves- and light travels at the same speed as electromagnetic waves. :)

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3 years ago

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A rock dropped down a well takes 1.8 s to hit the water. How far below the top of the well is the surface of the water

Brut [27]

Answer: 15.87 m

From the equation of motion:

$s=ut+\frac{1}{2}at^2$

where, $s$ is the distance traveled, $u$ is the initial velocity, $a$ is the acceleration and $t$ is the time.

The rock free falls under gravity. Initial velocity, $u=0 m/s$ , $a=g=9.8m/s^2$

It took $t=1.8 s$ for rock to hit the water.

Substitute the values in the given equation:

$\Rightarrow s=0+\frac{1}{2}9.8m/s^2\times(1.8s)^2=15.87 m$

Hence, the water is 15.87 m below the top level of the well.

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4 years ago

The following voltage drops are measured across three resistors in series: 5.5 V. 8.2 V. and 12,3 V. What is the value of the so

DiKsa [7]

Answer:

26 V

Explanation:

Given:

The three resistors 5.5 V. 8.2 V. and 12,3 V. are connected in series.

Now we have to find out the source voltage to which these resistors arc connected ?

Solution:

As we know in series the magnitude of current is uniform but the voltage divides between the resistors supplied from source voltage.So the magnitude of source voltage is, 5.5 V + 8.2 V + 12.3 V = 26 V

Hence, the value of the source voltage to which these resistors are connected is 26 V

7 0

3 years ago

You compress 0.5 moles of a gas at constant pressure from 4 liters to 1 liter while 2625 J of heat is removed, the temperature d

Xelga [282]

Answer:

The work energy added to the gas is

W = -72.48472 kJ

Explanation:

For constant pressure process

Work is given W = p× $(V_{f} - V_i)$

However dH = m× $c_{p} (T_2-T_1)$ = 1875 J

For mass m, dQ = 2625 J

That is m×1875 = 2625 or m = 2625/1875 = 1.4 kg

Therefore work doneper unit mass of gas is -W = p×(v₂ - v₁)

but pv = RT therefore work done per unit mass = -R×(T₂ - T₁) = -R×ΔT and

ΔT = 180.4K

Work done = -1.4×0.287×180.4 = -72.48472 kJ

8 0

4 years ago