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romanna [79]
3 years ago
13

UN BARCO NAVAL ENVÍA UNA SEÑAL A UN SUBMARINO QUE SE ENCUENTRA EN EL MAR DEBAJO DEL BARCO, SI ESTA SEÑAL TIENE UNA LONGITUD DE O

NDA DE 0.95CM, VIAJA A 558KM/H Y TARDA 3 SEGUNDOS EN LLEGAR AL SUBMARINO CALCULAR:
a) LA FRECUENCIA DE LA SEÑAL EMITIDA POR EL BARCO

b) EL PERIODO DE LA SEÑAL EMITIDA POR AL BARCO

c) LA PROFUNDIDAD DEL SUBMARINO
Physics
1 answer:
VLD [36.1K]3 years ago
4 0
NOooOoIooOOi Hsushrhndndnrbrbr rgehrbhrhrbr r he rjrnd
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Answer:

16 km

Explanation:

Drawing a right triangle to model the problem helps. I started by drawing the lines of the triangle to model the hiker's journey- a vertical straight line for 11 km north and then a horizontal line connected to the top of it for 11 km east; I then drew the hypothenuse to connect the two lines.

The hypothenuse is what we have to solve for, so we will use the Pythagorean Theorem, a^2 + b^2 = c^2. Since both distances are 11 km both a and b in the equation are 11.

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