3 years ago

What is the changing relationship between volume and surface area as an object get bigger?

1 answer:

soldier1979 [14.2K]3 years ago

8 0

As the cube size increases or the cell gets bigger , then the surface area to volume ratio - SA:V ratio decreases. When an object/cell is very small, it has a large surface area to volume ratio, while a large object/ cell has a small surface area to volume ratio.

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What is the cause of atmospheric pressure.

marusya05 [52]

Explanation:

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2 years ago

An astronaut on Earth notes that in her soft drink an ice cube floats with 9/10 of its volume submerged. If she were instead in

riadik2000 [5.3K]

Answer:

B) with 9/10 submerged

Explanation:

$m$ = mass of ice cube

$\rho$ = density of soft drink

$V$ = Volume of soft drink displaced

ice cube floats in the soft drink when the force of buoyancy on it balances its weight. Force of buoyancy acting on the cube in upward direction is same as the weight of the soft drink displaced. hence we can write

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3 years ago

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Answer:

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2 years ago

Noble gases, such as argon and neon, are known for being extremely non-reactive. Neon and argon are non-reactive because they A.

Greeley [361]

B. have eight electrons in their outer shell

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2 years ago

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A 3.50-meter length of wire with a cross-sectional area of 3.14 × 10-6 meter2 is at 20° Celsius. If the wire has a resistance of

maks197457 [2]

Answer:

$5.6\times 10^{-8}\ Ohm.m$

Explanation:

Resistivity is given by $\rho=\frac {AR}{L}$ where A is cross-sectional area, R is resistance, L is the length and $\rho$ is the reistivity. Substituting 0.0625 for R, 3.14 × 10-6 for A and 3.5 m for L then the resistivity is equivalent to

$\rho=\frac {3.14\times 10^{-6}\times 0.0625}{3.5}=5.60714285714285714285714285714285714285\times 10^{-8}\approx 5.6\times 10^{-8}\ Ohm.m$

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3 years ago