The number of possible combinations is given by
... C(18, 3) = 18!/(3!(18-3)!) = 18·17·16/(3·2·1) = 816 . . . . possible combinations
_____
There are 18 ways to choose the first one; 17 ways to choose the second one, and 16 ways to choose the 3rd one. The same 3 students can be chosen in any of 3! = 6 different orders, so the product 18·17·16 must be divided by 6 to get the number of possible combinations in which order doesn't matter.
Answer:
none of the two graphs in the pic.
it should be one in the II quadrant
Step-by-step explanation:
the plus four means to move 4 to the left
the plus 2 means to move up 2
That would make the vertex in the II quadrant.
Answer:
The correct option should have been 
.
Step-by-step explanation:
Given the expression
solving the expression
Remove parentheses: (a) = a
Group like terms
Add similar elements
It is clear that not a single given option is . It means no option is correct. It seems you mistyped the correct options.
The correct option should have been .
Send a picture of it ok then i answer
