We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
</span>- 1/(2-c)=-1/-(c-2)=1/(c-2)
(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2)
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)
(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14
the solution is c=14
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or
<span>all real numbers except c=-2 and c=2</span>
Answer:
i belive the answer is B
Step-by-step explanation:
Answer:-7x+2y=2
Step-by-step explanation:
(-2x+y=8)-(5x-y=6)
(-2x+y=8)> this side change since it’s negative
(-2x+y=8) - (-5x+y=-6)
-7x+2y=2
Answer:
21
Step-by-step explanation:
You do the parentheses first, so 27/9 = 3
10-3 = 7
3 * 7 = 21
Answer:
____________
the answer is B
___________
explanation
Factor out the greatest common factor from each group.
Group the first two terms and the last two terms.
(x^2 - 2x) - 3xy + 6y
Factor out the greatest common factor (GCF) from each group.
x(x - 2) - 3y (x - 2)
Factor the polynomial by factoring out the greatest common factor, x - 2
(x - 2) (x - 3y)
