Please help me out.........
2 answers:
Answer:
vertex = (- 3, 24)
Step-by-step explanation:
Given a quadratic in standard form y = ax² + bx + c : a ≠ 0, then
The x- coordinate of the vertex is
= -
y = - x² - 6x + 15 ← is in standard form
with a = - 1, b = - 6, thus
= -
= - 3
Substitute x = - 3 into the function for corresponding value of y
y = - (- 3)² - 6(- 3) + 15 = - 9 + 18 + 15 = 24
vertex = (- 3, 24)
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Answer:
The distance between the points is approximately 6.4
Step-by-step explanation:
The given coordinates of the points are;
(2, -2), and (6, 3)
The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;
Substituting the known 'x', and 'y', values for the coordinates of the points, we have;
Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.