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IRINA_888 [86]
3 years ago
13

Solve the equationy=5x-2 for x. ​

Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer: x + y/5 - 2/5

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Sasha ordered a set of green and blue pins. She received 20 pins in all. 10 of the pins were green. What percentage of the pins
arlik [135]

Answer:

50%

Step-by-step explanation:

10 of the pins were green

there are 20 pins in total

10/20 of the fries are green

10/20=1/2=50/100

50/100=50%

5 0
3 years ago
50 POINTS!!! In rectangle ABCD, AB = 6 cm, BC = 8 cm, and DE = DF. The area of triangle DEF is one-fourth the area of rectangle
aalyn [17]

Answer:

EF=4\sqrt{3}

Step-by-step explanation:

In rectangle ABCD, AB = 6, BC = 8, and DE = DF.

ΔDEF is one-fourth the area of rectangle ABCD.

We want to determine the length of EF.

First, we can find the area of the rectangle. Since the length AB and width BC measures 6 by 8, the area of the rectangle is:

A_{\text{rect}}=8(6)=48\text{ cm}^2

The area of the triangle is 1/4 of this. Therefore:

\displaystyle A_{\text{tri}}=\frac{1}{4}(48)=12\text{ cm}^2

The area of a triangle is half of its base times its height. The base and height of the triangle is DE and DF. Therefore:

\displaystyle 12=\frac{1}{2}(DE)(DF)

Since DE = DF:

24=DF^2

Thus:

DF=\sqrt{24}=\sqrt{4\cdot 6}=2\sqrt{6}=DE

Since ABCD is a rectangle, ∠D is a right angle. Then by the Pythagorean Theorem:

(DE)^2+(DF)^2=(EF)^2

Therefore:

(2\sqrt6)^2+(2\sqrt6)^2=EF^2

Square:

24+24=EF^2

Add:

EF^2=48

And finally, we can take the square root of both sides:

EF=\sqrt{48}=\sqrt{16\cdot 3}=4\sqrt{3}

6 0
3 years ago
Read 2 more answers
Verify that cos squared A plus Sin squared A is equal to 1 if A is equal to 90 degrees
Scilla [17]

Answer:

see explanation

Step-by-step explanation:

To verify cos²A + sin²A = 1 with A = 90° , then

cos²90° + sin²90°

= (0)² + (1)²

= 0 + 1

= 1

3 0
3 years ago
Find the difference equation<br> Y= a / x +b
Art [367]

Answer:

y+a+x=b

Step-by-step explanation:

hope it's work ty make me brainless tyy

7 0
2 years ago
Regular triangular pyramid has 6 cm long base edge and slant height k=9 cm. Find the lateral area of the pyramid.
gregori [183]

Answer:

81 cm²

Step-by-step explanation:

Since, the lateral face of a triangular pyramid is a triangle,

Given,

The base edge or the base of one lateral face of pyramid, a = 6 cm,

And, the slant height or the height of the face, k = 9 cm,

Thus, the area of one lateral face of the pyramid,

A=\frac{1}{2}\times a\times k

=\frac{1}{2}\times 6\times 9

=\frac{54}{2}

=27\text{ square cm}

We know that, a Regular triangular pyramid has 3 lateral faces,

Hence, the total lateral area of the pyramid,

L.A.=3\times\text{ The area of one lateral face}

=3\times 27

=81\text{ square cm}

5 0
3 years ago
Read 2 more answers
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