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galben [10]
3 years ago
9

You want to estimate the proportion of students at OSU who have ever used an online dating app. You select a random sample of 14

0 OSU students and find that 43% have used an online dating app. If you want to construct a 99% confidence interval, what will the margin of error be? Try not to do a lot of rounding along the way until you get to the end of your calculations?
Mathematics
1 answer:
Dima020 [189]3 years ago
7 0

Answer:

The margin of error for the proportion of students at OSU who have ever used an online dating app in 99% confidence level is 10.8%

Step-by-step explanation:

margin of error (ME) around the mean can be found using the formula

ME=z*\sqrt{\frac{p*(1-p)}{N} } where

  • z is the corresponding statistic in the given confidence level (2.58)
  • p  the proportion of students at OSU who have ever used an online dating app in the random sample. (0.43)
  • N is the sample size (140)

Putting the numbers in the formula we get

ME=2.58*\sqrt{\frac{0.43*0.57}{140} } ≈ 0,10795 ≈ 10.8%

Then the confidence interval for the proportion of students at OSU who have ever used an online dating app in 99% confidence level would be 43%±10.8%

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Answer:

  see the attached for a graph

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answer:

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