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AnnZ [28]
4 years ago
14

3. Concentric circles (one smaller circle inside another). As

Chemistry
1 answer:
Agata [3.3K]4 years ago
8 0

Answer:

Bohr's "planetary project" was widely accepted because he was able to explain a factor that Ruthford failed to achieve. Bohr was able to explain how electrons and energy worked in a simple atom, such as hydrogen, which consists of an electron orbiting a single proton.

In addition, he was able to explain, using the principles of gravity, how electrons do not fall on top of the proton but rather orbit around the proton.

Explanation:

Danish physicist Niels Bohr proposed an atomic model for the hydrogen atom which was later extended to other elements. Its model is based on the Solar System, in which the planets rotate around the sun. For Bohr, electrons rotate in orbit around the atomic nucleus grouped into energy levels.

Until 1913, there was no satisfactory model that explained even the simplest of atoms - hydrogen, which consists of an electron orbiting a single proton.

By assigning the concept of energy levels, Bohr was able to create a version of the hydrogen atom that was possibly stable and satisfying spectral observations. Until then, all theoretical predictions suggested that it should not exist for more than a split second - a failure that bothered physicists a great deal. It was therefore a monumental advance.

Bohr was also able to explain why electrons do not fall on protons using concepts of gravity. In Bohr's atomic model, electrons rotate around the nucleus like planets around the sun. According to Bohr, an electron does not fall into the nucleus because it cannot: its orbits are like steps in a ladder. We may be in one or the other but not in two. Imagine the atom as a kind of tiny football stadium.

The core is in the center of the lawn. Electrons can run around the steps of the stands. From time to time, they jump from step to step. If they go up they use energy, down they release energy.

However, electrons can never leave the stands to invade the field. Bohr did not explain why the ban.

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What units are used to express energy transfer?
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It should be watts. <span>A </span>watt<span> is the number of </span>joules generated per second. <span>A kilocalorie is 4,184 </span>joules<span>, the amount of energy that will heat 1 kilogram of water by 1 degree </span>Celsius<span>. </span> 
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A 275-mL flask contains pure helium at a pressure of 752 torr. A second flask with a volume of 475 mL contains pure argon at a p
hichkok12 [17]

Answer:

  • Partial pressure He = 276 torr
  • Partial pressure Ar = 457 torr
  • Total pressure = 733 torr

Explanation:

Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.

Once the two flasks are connected and the stopock opened, the total volume is:

  • 275 + 475 = 750 mL

Now we use Boyle's law <em>twice</em>, to <u>calculate the new pressure of </u><em><u>each</u></em><u> gas</u>:

  • He ⇒ 752 torr * 275 mL = P₂He * 750 mL

P₂He = 276 torr

  • Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL

P₂Ar = 457 torr

Finally we <u>calculate the total pressure</u>, adding the partial pressures:

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4 0
3 years ago
10. What is the specific heat of an unknown substance if a 2.50 g sample releases 12 calories as its
Sergeu [11.5K]

Answer:

c = 4016.64 j/g.°C

Explanation:

Given data:

Mass of substance = 2.50 g

Calories release = 12 cal (12 ×4184 = 50208 j)

Initial temperature = 25°C

Final temperature = 20°C

Specific heat of substance = ?

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Solution:

Q = m.c. ΔT

ΔT  = T2 - T1

ΔT  = 20°C - 25°C

ΔT  = -5°C

50208 j = 2.50 g . c. -5°C

50208 j = -12.5 g.°C .c

50208 j /-12.5 g.°C =  c

c = 4016.64 j/g.°C

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La oxidación es cuando??
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Los dos átomos operan simultáneamente
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