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11Alexandr11 [23.1K]
3 years ago
10

A 275-mL flask contains pure helium at a pressure of 752 torr. A second flask with a volume of 475 mL contains pure argon at a p

ressure of 722 torr. If the two flasks are connected through a stopcock and the stopcock is opened, what is the partial pressure of each gas and the total pressure?
Chemistry
1 answer:
hichkok12 [17]3 years ago
4 0

Answer:

  • Partial pressure He = 276 torr
  • Partial pressure Ar = 457 torr
  • Total pressure = 733 torr

Explanation:

Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.

Once the two flasks are connected and the stopock opened, the total volume is:

  • 275 + 475 = 750 mL

Now we use Boyle's law <em>twice</em>, to <u>calculate the new pressure of </u><em><u>each</u></em><u> gas</u>:

  • He ⇒ 752 torr * 275 mL = P₂He * 750 mL

P₂He = 276 torr

  • Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL

P₂Ar = 457 torr

Finally we <u>calculate the total pressure</u>, adding the partial pressures:

  • Total pressure = P₂He + P₂Ar = 733 torr
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The question is incomplete, here is the complete question:

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The image is attached below.

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Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c

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We are given:

Volume of the container = 1.0 L

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For the given images:

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Putting values in expression 1, we get:

K_c=\frac{(4/1)^2}{(8/1)}\\\\K_c=2

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Putting values in expression 1, we get:

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Putting values in expression 1, we get:

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