Answer:
H = 20.5 hours
I = 19.5 Hours
Step-by-step explanation:
Start by creating a system.
I = time which the inlet pipe takes alone to fill the pond
H = time which the hose takes alone to fill the pond
10/I + 10/H = 10
H - I = 1
H = 20.5 hours
I = 19.5 Hours
Answer:
15.0
Step-by-step explanation:
Let's start by looking at triangle ORQ. Since RQ is tangent to the circle, we know that angle ∠ORQ is 90°. Then, since OR is equivalent to the radius of 5, RQ is 5√3, and side OQ is clearly larger than RQ, we can identify this as a 90-60-30 degree triangle. This makes side OQ have a length of 10, and angle ∠QOR, opposite of the second largest side, has the second largest angle of 60°, leaving ∠OQR with an angle of 30°.
The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)
Answer:
Neither even nor odd.
Step-by-step explanation:
f(x) = 2(x + 1)^3 = 2x^3 + 18x^2 + 54x + 54
f(-x) = -2x^3 + 18x^2 - 54x + 54
If it was even f(x) would be = f(-x) so it is NOT EVEN.
-f(x) = 2x^3 - 18x^2 + 54x - 54
So f(-x) is not = -f(x) so it is not ODD either.
Answer:
=0.3 per km²
Step-by-step explanation:
Population density is the population per uni area.
Area=πr² Where A is area and r is the radius of the circle.
A=3.14×34
=106.76km²
Population density = Population/Area
=32 antelopes/106.76 km²
=0.3 per km²
The population of antelopes within the given radius is 0.3 per km²
