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Vladimir [108]
4 years ago
12

How should you set the OHMS ADJust control on a multitester of analog VOM, for resistance measurements?

Computers and Technology
1 answer:
TiliK225 [7]4 years ago
6 0

In my day (my next door neighbor was a brontosaurus rex), there was a wheel on the front panel.

You shorted the input leads when the master switch was turned to ohms. Then you adjusted the wheel so that the meter read 0 on the right hand side of the scale. The zero is clearly marked. The ohmmeter on an analog Vom reads 0 on the right. Everything else has its zero on the left.

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Write an algorithm that reads 100 test points and finds the student with the highest result​
solmaris [256]

Answer:

ok

Explanation:

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3 years ago
The largest type of computer system with the most extensive storage capacity and the fastest processing speeds is a ________.
azamat
Super Computer. Hope I helped.
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Test if a number grade is an A (greater than or equal to 90). If so, print "Great!". Sample Run Enter a Number: 98 Sample Output
Debora [2.8K]

Answer:

Using Python language :

a = eval ( input ( "Enter a mark please"))

if ( a <0){

print ("Invalid mark")};

else if (a >=90 && a <=100){ print

( "GREAT")};

Explanation:

7 0
3 years ago
Write a static method called bothStart that allows the user to input two Strings and returns the String that is the longest subs
marishachu [46]

Answer:

  1.    public static String bothStart(String text1, String text2){
  2.        String s = "";
  3.        if(text1.length() > text2.length()) {
  4.            for (int i = 0; i < text2.length(); i++) {
  5.                if (text1.charAt(i) == text2.charAt(i)) {
  6.                    s += text1.charAt(i);
  7.                }else{
  8.                    break;
  9.                }
  10.            }
  11.            return s;
  12.        }else{
  13.            for (int i = 0; i < text1.length(); i++) {
  14.                if (text1.charAt(i) == text2.charAt(i)) {
  15.                    s += text1.charAt(i);
  16.                }else{
  17.                    break;
  18.                }
  19.            }
  20.            return s;
  21.        }
  22.    }

Explanation:

Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).  

<em />

Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).

There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).

If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.

The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>

<em />

At the end, return the s as output (Line 21).

5 0
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Answer:

WiFi, Ethernet, Broadband, Dial-up. Any of those.

Explanation:

Network connections are all different. Those listed are some of the many examples of network connections.

7 0
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