Answer:
The answer is: $22
Explanation:
In order to calculate the cost of skipping practice, we have to calculate the total sum of the deficit incurred within the period, and this includes the money that would have been earned during that hour of practice if it had been attended (opportunity cost of time), and the admission fee into the carnival. This calculation is shown below:
Opportunity cost of time = $13
cost of admission into carnival = $9
Total cost of skipping practice = opportunity cost of time + cost of admission into carnival
= 13 + 9 = $22
Answer:
value of the bond = $2,033.33
Explanation:
We know,
Value of the bond, ![B_{0} = [I * \frac{1 - (1 + i)^{-n}}{i}] + \frac{FV}{(1 + i)^n}](https://tex.z-dn.net/?f=B_%7B0%7D%20%3D%20%5BI%20%2A%20%5Cfrac%7B1%20-%20%281%20%2B%20i%29%5E%7B-n%7D%7D%7Bi%7D%5D%20%2B%20%5Cfrac%7BFV%7D%7B%281%20%2B%20i%29%5En%7D)
Here,
Face value of par value, FV = $2,000
Coupon payment, I = Face value or Par value × coupon rate
Coupon payment, I = $2,000 × 6.04%
Coupon payment, I = $128
yield to maturity, i = 6.1% = 0.061
number of years, n = 15
Therefore, putting the value in the formula, we can get,
![B_{0} = [128 * \frac{1 - (1 + 0.061)^{-7}}{0.061}] + [\frac{2,000}{(1 + 0.061)^7}]](https://tex.z-dn.net/?f=B_%7B0%7D%20%3D%20%5B128%20%2A%20%5Cfrac%7B1%20-%20%281%20%2B%200.061%29%5E%7B-7%7D%7D%7B0.061%7D%5D%20%2B%20%5B%5Cfrac%7B2%2C000%7D%7B%281%20%2B%200.061%29%5E7%7D%5D)
or, ![B_{0} = [128 * \frac{1 - (1.061)^{-7}}{0.061}] + [\frac{2,000}{(1.061)^7}]](https://tex.z-dn.net/?f=B_%7B0%7D%20%3D%20%5B128%20%2A%20%5Cfrac%7B1%20-%20%281.061%29%5E%7B-7%7D%7D%7B0.061%7D%5D%20%2B%20%5B%5Cfrac%7B2%2C000%7D%7B%281.061%29%5E7%7D%5D)
or, ![B_{0} = [128 * \frac{0.3393}{0.061}] + 1,321.3635](https://tex.z-dn.net/?f=B_%7B0%7D%20%3D%20%5B128%20%2A%20%5Cfrac%7B0.3393%7D%7B0.061%7D%5D%20%2B%201%2C321.3635)
or, ![B_{0} = [128 * 5.5623] + 1,321.3635](https://tex.z-dn.net/?f=B_%7B0%7D%20%3D%20%5B128%20%2A%205.5623%5D%20%2B%201%2C321.3635)
or,
$711.9738 + 1,321.3635
Therefore, value of the bond = $2,033.33
Answer:
S/N ACCOUNT DEBIT CREDIT
1 Equipment $22,000
Cash $22,000
Being payment for new component expected to increase the
equipment’s productivity by 10% a year
2. Equipment Repairs expenses $6,250
Cash $6,250
Being payment for equipment repair
3. Equipment $14,870
Cash $14,870
Being payment for equipment repair to prolong the useful life
the asset
Explanation:
The initial cost incurred in acquiring an asset is debited to asset account, subsequently every other cost spent on the assets are either expenses against the earning of that period or expensed over many years over the useful life of the asset.
Capitalization is the recognition of an expense as an asset in the balance sheet rather than expenses in the income statement.
The payment of $22,000 paid for the equipment productivity must be capitalized, that is added to the cost of the asset because it is a cost that is expected to increase the equipment’s productivity by 10% a year.
The $6,250 paid for normal repair is a revenue items which is to be expensed against the earning of that period.
The $14,870 paid for repairs which will increase the useful life of the equipment from four to five years is a capital expenditure which should capitalized, that is added to the cost of the asset.
Steven needs to create a budget that will list all of his expenses each month with regards to the income he brings in. Once Steven sits down and creates the budget he will see the money that is left over once he is done paying all of his necessary bills. The money that is left over can be saved to purchase a new car.
Answer:
variable cost per unit = 46
fixed cost 188680
Explanation:
The high-low method consist in compare each frame to get the variable and fixed components
5440 high
2040 low
3400 difference
437920 high
281520 low
156400 difference
variable cost =15600/3400
variable cost = 46
the reasoning is that the additional 3400 units generated that cost.
Now:
we múltiple by the units by the production and get total variable
46 * 2040 = 93840 total variable
lastly total cost - total variable = fixed
281520 - 93840 = 188680