CAN I PLSS GET HELP ASAP!!? What slope- intercept form equation represents the line

Which algebraic expression represents “Marcus ran four times as far this week”? 4 + n 4n n – 4

disa [49]

Answer:

The Answer would be 4n

Step-by-step explanation:

Since Marcus ran four times as far this week, we need to know how far he ran last week in order to solve this expression. Since we do not know this information it becomes our variable (n). From the statement we can also infer that there is multiplication since he states the word "times". Therefore our Algebraic Expression would be the following.

P = 4n

P being distance ran by Marcus, and n being distance ran last week by Marcus.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

5 0

2 years ago

Read 2 more answers

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation option

denis-greek [22]

Answer:

The probability that he teleports at least once a day = $\mathbf{\frac{5}{9}}$

Step-by-step explanation:

Given -

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.

Total no of outcomes = 3

P( He not choose teleport in the morning ) = $\frac{2}{3}$

P( He not choose teleport in the evening ) = $\frac{2}{3}$

P ( he choose teleports at least once a day ) = 1 - P ( he not choose teleports in a day )

= 1 - P( He not choose teleport in the morning ) $\times$ P( He not choose teleport in the evening )

= $1 - \frac{2}{3}\times\frac{2}{3}$

= $\frac{5}{9}$

3 0

2 years ago

A company has two manufacturing plants with daily production levels of 5x+11 items and 2x-3 items, respectively. The first plan

Elan Coil [88]

Answer:

alr 5x+11 and 2x-3

5x+11=16x

2x-3=-1x

Step-by-step explanation:

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4 0

2 years ago

Use now it actually works I used one of them but not all of it I thought it was cap it it works happy holidays the uteber is the

Kobotan [32]

So basically what you do is that you have to go to safari and go to tweak door and then download brainly++

7 0

1 year ago

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

2 years ago