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3 years ago

Which one does not belong 3:4, 9:12, 12:15, 12:16 and why

Mathematics

2 answers:

vivado [14]3 years ago

5 0

3:4 can not belong because it doesn't have 12 like other does.

svp [43]3 years ago

3 0

3:4 is the answer. Look at it like a pattern. 9:12, 3 goes into both of them, 12:15, 3 goes into both of them, 12:16, 4 goes into both of them. However nothing goes into both the numbers in 3:4.

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Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview

mario62 [17]

Answer: The required solution is

$y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.$

So, the general solution of the given equation is

$y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.$

According to the given conditions, we have

$y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

and

$y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.$

From equation (ii), we get

$B=\dfrac{7}{3}.$

Thus, the required solution is

$y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.$

7 0

3 years ago

a 5th grade volleyball team scored 32 points in one game. of those points 2/8 were scored in the second half. how many points we

Degger [83]

Answer:

Number of points scored in the first half of the match is 24 points.

Step-by-step explanation:

Total point scored in the volleyball game = 32

Let us assume the points scored in the first half = m

and the point scored on the second half = 2/8 of (Total points)

= $\frac{2}{8} \times 32 = 8$

⇒ The number of points s cored in the second - half = 8 points

Now, Points in FIRST half+ Points in SECOND half= Total Points

⇒ m+ 8 = 32

or, m = 32 - 8 = 24

⇒ m = 24

Hence, the number of points scored in the first half is 24 points.

4 0

3 years ago

Plzzzz help mee plzzzzz plzzzzz

FromTheMoon [43]

Answer:

1. B

2. Seven Hundred thousand nine hundred and four

Step-by-step explanation:

3 0

3 years ago

If i know the area of a square, how do i find the side length?

Talja [164]

Answer:

Um im no expert but

Step-by-step explanation:

length is a type of measurement, that tells how long something is or how wide it is. hoped this helped^^

6 0

3 years ago

The product of 4 and the difference between 8 and 3 wrote as an expression

masha68 [24]

Answer:

4(8-3)

Remember to use PEMDAS if you have to solve :)

5 0

3 years ago

Read 2 more answers