Consider the length of diagonal is 8.5 cm instead of 8.5 m because length of perpendiculars are in cm.
Given:
Length of the diagonal of a quadrilateral = 8.5 cm
Lengths of the perpendiculars dropped on it from the remaining opposite vertices are 3.5 cm and 4.5 cm.
To find:
The area of the quadrilateral.
Solution:
Diagonal divides the quadrilateral in 2 triangles. If diagonal is the base of both triangles then the lengths of the perpendiculars dropped on it from the remaining opposite vertices are heights of those triangles.
According to the question,
Triangle 1 : Base = 8.5 cm and Height = 3.5 cm
Triangle 2 : Base = 8.5 cm and Height = 4.5 cm
Area of a triangle is
Using this formula, we get
and
Now, area of the quadrilateral is
Therefore, the area of the quadrilateral is 34 cm².
Using the equation of the proportional relationship:
Average rate of speed = 60
Time taken to go 300 miles = 5 hrs
Distance travelled in 2.5 hrs = 150 miles
<h3>What is a Equation of a Proportional Relationship?</h3>
A equation of a proportional relationship models the relationship between two variables, x and y, that has a constant of k. It is expressed as y = kx.
Given the following:
Equation: d = 60t
d = distance in miles
t = time in hours
Average rate of speed for the bus = k = 60
Time (t) it would take to go 300 miles (d):
300 = 60(t)
300/60 = t
t = 5 hours
Distance (d) it would travel in 2.5 hours (t):
d = 60(2.5)
d = 150 miles
Learn more about the equation of a proportional relationship on:
brainly.com/question/6869319
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Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
Answer:
<h3>18:00 </h3>
Step-by-step explanation:
6:00 PM equals 18:00 in 24 hrs clock time.
<h3>Hope it helps you.. </h3>
Use a factor<span> tree to express </span>60<span> as a </span>product<span> of prime </span>factors<span>. So the prime factorization of </span>60<span> is 2 × 2 × 3 × 5, which can be written as 2 </span>2<span> × 3 × 5.</span>
