Answer:
y-10 = -1 * x+ (-4)
Step-by-step explanation:
Answer: y-intercept: (0,-6)
Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
Here you go. I hope this will help
8 3/4 + 9 5/9 Add 8 and 9
17 + 3*9/4*9 + 5*4/9*4 Find common denominator
17 + 27/36 + 20/36 Add
17 + 47/36 Convert into mixed fraction
17 + 1 11/36 Simplify mixed fraction
18 11/36. Answer
If you need the decimal form, it is 18.31. But other than that, the answer is 18 11/36.
