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3 years ago

Write an equation of a line in a slope-intercept form that passes through (-2,1) with a slope of 5.

1 answer:

8 0

If they give you a point and slope, use point slope form.
Then simplify to get slope intercept form (y = mx + b)
slope (m) = 5
(-2, 1)

y - y1 = m(x - x1)
y - 1 = 5(x + 2)
y - 1 = 5x + 10

y = 5x + 11

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Write the equation of the line in slope-intercept form using y=mx+b

aivan3 [116]

Y= 1/4x+3, 3 is the y intercept and 1/4 is the slope. For slope use rise over run

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3 years ago

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Rickey has been commissioned to paint a mutual that is allowed to have an area 60 square meters to make the rectangulr shape of

Svet_ta [14]

Answer:

Length of the mural should be 20.78 m

Step-by-step explanation:

Let the length of the mural be L and the width W

Area = L × W = 60 m²

Ticket wants the L = 15 + 2W

Substitute for L in the Area eqn

(15 + 2W) × W = 60

15W + 2W² = 60

2W² + 15W - 60 = 0

Solving the quadratic equation

W = 2.89 m or - 10.39 m

Obviously, the width cannot be negative,

So, W = 2.89 m

L = 15 + 2W = 15 + 2(2.89) = 20.78 m

Check - L × W = 20.78 × 2.89 = 60 m²

Hope this Helps!!!

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3 years ago

1) If y = x3 + 2x and dx/ dt = 5, find dy/dt when x = 2. Give only the numerical answer. For example, if dy, dt = 3, type only 3

Semenov [28]

Answer:

a) 70

b) 10π ft²/ft

c) 0.24 ft/sec

Step-by-step explanation:

1) y = x³ + 2x

$\frac{dy}{dt}=\frac{d(x^3+2x)}{dt}$

$\frac{dy}{dt}$ = $3x^2\frac{dx}{dt}+2\frac{dx}{dt}$

at $\frac{dx}{dt}=5$ and x = 2

$\frac{dy}{dt}$ = $3(2)^2\times(5)+2\times(5)$

$\frac{dy}{dt}$ = 60 + 10 = 70

2) A = πr² ft²

$\frac{dA}{dr}=\frac{d(\pi r^2)}{dr}$

$\frac{dA}{dr}$ = 2(πr)

at r = 5 ft

$\frac{dA}{dr}$ = 2(π × 5) ft²/ft

$\frac{dA}{dr}$ = 10π ft²/ft

3) From Pythagoras theorem

Base² + Perpendicular² = Hypotenuse²

Thus,

B² + P² = H² .............(1)

here, H = length of the ladder

P is the height of the wall

B is the distance from the wall at bottom

B² + P² = 25² ...........(1)

at B = 20 ft

20² + P² = 25²

P² = 625 - 400

P = √225

P = 15 ft

differentiating (1) with respect to time, we get

$2B\frac{dB}{dt}+2P\frac{dP}{dt}=0$

at B = 20 ft, $\frac{dB}{dt} = 0.18$ and P = 15 ft

⇒ 2(20)(0.18) + $2(15)\frac{dP}{dt}$ = 0

$30\frac{dP}{dt}$ = - 7.2

$\frac{dP}{dt}$ = - 0.24 ft/sec (Here negative sign depicts the ladder slides down)

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4 years ago

How many 7-digit phone numbers can be formed if the first digit cannot be 0 or 1 and if no digit can be repeatd?

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8x10x9x8x7x6x5= 1209600

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4 years ago

How long does it take to drive 25 miles at 60 mph?

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60 mph = 1 mile per minute ( 60 minutes per hour)

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