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3 years ago

Can anyone answer this question for me?

Mathematics

1 answer:

Oksanka [162]3 years ago

6 0

Answer:

The answer is about 1.732, the exact form being $\sqrt{3}$ .

Step-by-step explanation:

The square root of 12 is 3.4641. You then divide this by 2 and you get approximately 1.732. This in the exact form is $\sqrt{3}$ .

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An equilateral triangle has sides of length 2 units. A second equilateral triangle is formed having sides that are 150% of the l

murzikaleks [220]

Answer:

The percent increase in the perimeter is 337.5%

Step-by-step explanation:

The easiest way to approach this problem is by using consecutively the simple rule of three.

If the first triangle has sides of length two then, we can compute the second triangle's sides length as follows:

2 units------100%

X units------150%

this way

$X = 2*\frac{150}{100}\\ X =2*1.5\\X=3units$ .

Now for the third triangle we repeat the same process

3 units------100%

X units------150%

getting that the length of the sides for the third triangle is

$X = 3*\frac{150}{100}\\ X =3*1.5\\X=4.5units$ .

Now for the last triangle we repeat the same process

4.5 units------100%

X units------150%

getting that the length of the sides for the last triangle is

$X = 4.5*\frac{150}{100}\\ X =4.5*1.5\\X=6.75units$ .

Now, we need to know the perimeter of the first and last triangle. This can be calculated as the sum of the length of the sides of the triangle.

For the first triangle

$P_{first}=2+2+2\\P_{first}=6$

and for the last triangle

$P_{first}=6.75+6.75+6.75\\P_{first}=20.25$ .

To compute the percent increase in the perimeter from the first to the fourth triangle we will use one last simple rule of three (this time the percentage will be the variable)

6 units------100%

20.25 units------X%

$X = 100\frac{20.25}{6}\\ X=337.5\%$ .

4 0

3 years ago

What is the formula to find distance in coordinate geometry, given coordinates (x_1, y_1), (x_2, y_2)? (valid variables for this

madreJ [45]

Answer:

The distance formula is: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Given:

Two points on a coordinate plane are given as:

$(x_1,y_1)\ and\ (x_2,y_2)$

Now, let the points be $A(x_1,y_1)\ and\ B(x_2,y_2)$ and let 'd' be the distance between the two points.

Now, join the points A and B to make a line segment AB.

Also, draw a right angled triangle ABC right angled at point C. Point C is is the intersection of horizontal and vertical lines drawn from points A and B respectively as shown in the figure below.

From the triangle ABC, we observe that:

AB = $d$