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TEA [102]
3 years ago
15

Suppose that you are standing 150 feet from a building and the angle of elevation to the top of the building is 42°. What is the

building's height?
Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

135.06 feet

Step-by-step explanation:

Since the side of the building makes a right triangle with the ground and you know one side length and the degree angle between you and the top of the building we can use trigonometric function to find the height of the building. So since we know one side other than the hypotenuse we can use tangent to solve. Tangent is the opposite side over the adjacent side of the known angle.

opposite side = x

adjacent side = 150 feet

angle = 42°

tan(42°) = x/150 feet

150 feet * tan(42°) = x

x = 135.06 feet

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Alja [10]

Answer:

1. 14

2.400 pieces

Step-by-step explanation:

1. 8.02+6.1= 14.12, since its less than 14.5 you must round down to 14

2. remember 1 meter is 100 centimeters, thus to find how many centimeters are in 24 m multiply 100 by 24. this will get 2400 centimeters

divide 2400/6 and you will get 400

5 0
3 years ago
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Determine the value of x for the diagram shown.
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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What are the coordinates of the terminal point determined by t=20pi/3?
attashe74 [19]

Answer:

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3 0
3 years ago
In △ABC, D is a point on side AC¯¯¯¯¯¯¯¯ such that BD=DC and ∠BCD measures 70∘. What is the degree measure of ∠ADB?
777dan777 [17]
If angle BCD measures 70° then so does angle DBC (because you have formed an isoceles triangle inside the larger ΔABC and the two legs are equal so the two angles have to be equal.   So we have a two 70° angles which leaves 40° for the 3rd angle, which is ∠BDC.   

Since ∠BDC and ∠ADB are supplementary (180°) - that leaves 140° for ∠ADB and is our answer
5 0
3 years ago
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Dovator [93]

Answer:

Since ZE and ZF are vertical angles, they are congruent.

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x = 5

7 0
3 years ago
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