Over which interval(s) is the function decreasing?
Let x be the original radius. Given that a semicircle will have an arc length of half of a circumference and C=2pr, the arc length will be just pr.
Now the difference of arc is then going to be:
p(6+x)-px
p(6+x-x)
6p inches
So the arc will be 6p inches longer. Or if you wish to approximate...
≈18.85 inches
Ln20+ln5=2ln x
ln(20*5) = ln x^2
ln 100 = ln x^2
100 = x^2
x = 10 second option
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....sorry hope this is right goodluck!
