3 years ago

Linear relations I need help on these two

1 answer:

4 0

a linear equation is an equation that may be put in the form where are the variables, and are the coefficients, which are often real numbers. The coefficients may be considered as parameters of the equation, and may be arbitrary expressions, provided they do not contain any of the variables.

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Absolute Values Inequalitties I x I + 3 > 4

Aneli [31]

$| x | + 3 > 4\\
|x|>1\\
x>1 \vee x$

8 0

3 years ago

4 <img src="https://tex.z-dn.net/?f=4x%20-%203%20%3D%202x%20%2B%207%20find%20x%20" id="TexFormula1" title="4x - 3 = 2x + 7 fi

natima [27]

Answer:

x=5

Step-by-step explanation:

That is your answer .

First you do 4x-3+3=2x+7+3

then,4x=2x+10,then

subtract 2x from both side

4x-2x=2x+10-2x

simplify

2x=10

divide both sides by 2 2x/2=10/2

simplfy and you get x=5

Hope this helps :)

4 0

3 years ago

How do you solve 3^2x=81

qwelly [4]

Answer:

x=2

Step-by-step explanation:

3^2x = 81

3^2x = 3^4

Compare powers

2x = 4

x = 2

4 0

3 years ago

Read 2 more answers

Help help help and help

Alexus [3.1K]

Answer:

x= 8.5 and y= 2

Step-by-step explanation:

6 0

3 years ago

One uranium atom has a mass of 3.95 x 10^-22 grams.

creativ13 [48]

Remember
(ab)/(cd)=(a/c)(b/d)
and
$\frac{x^n}{x^m}=x^{n-m}$

1kg=1000g=1*10^3g
hmm, I estimate, 4 of them

x=number of attoms
mass of 1 times x=1*10^3
3.95*10^-22 times x=1*10^3
divide both sides by 3.95*10^-22
x= $\frac{1*10^3}{3.95*10^{-22}}= (\frac{1}{3.95} )( \frac{10^{3}}{10^{-22}} )$ = $0.25316*10^{25}$ = $2.5316*10^{24}$
a million has 9 zeroes
so 24 zeroes is alot that is a septillion, so there are 2.5316 septillion uranium atoms in 1kg

a. 4
b. underestimate

5 0

3 years ago