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OlgaM077 [116]
3 years ago
5

Can someone help me with this one?

Mathematics
1 answer:
hodyreva [135]3 years ago
5 0

Answer:1

Step-by-step explanation:

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Find a39 of the arithmetic sequence given a1 = -28 and d = -4.
seraphim [82]

Hello !

a_{n} = a_{1} + (n - 1) \times d

a_{39} =  - 28 + (39 - 1) \times ( - 4) =  - 28 + 38 \times ( - 4) =  - 180

8 0
2 years ago
Determine the zeros of the function <br> 5) y=-x² + 2x + 1
Rus_ich [418]
<h3>Zeros of function are x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}</h3>

<em><u>Solution:</u></em>

<em><u>We have to find the zeros of the function</u></em>

y = -x^2 + 2x+1

Find the zeros of function:

-x^2 + 2x+1 = 0\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-1,\:b=2,\:c=1\\\\x  =\frac{-2\pm \sqrt{2^2-4\left(-1\right)1}}{2\left(-1\right)}

Simplify\\\\x=\frac{-2 \pm \sqrt{4+4}}{-2}\\\\x =\frac{-2 \pm \sqrt{8}}{-2}\\\\Simplify\\\\x =\frac{-2 \pm 2 \sqrt{2}}{-2}\\\\x = 1 \pm \sqrt{2}

We have two zeros

x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}

Thus zeros of function are x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}

3 0
3 years ago
Read 2 more answers
Someone help pleaseee!!
iren [92.7K]
Hello : 
\frac{1}{ \sqrt[3]{ x^{5} } } =  \frac{1}{ x^{ \frac{5}{3} } }=  x^{- \frac{5}{3} }

3 0
3 years ago
I need help with letters (D) and (E). My model equation from letter (C) is: P = -55/4 t+ 340.
IceJOKER [234]

Answer:

(a) The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope is m = -55/4

The slope means the rate of decreases of the owl population was 55/4

per year (P decreased by 55/4 each year)

(c) The model equation is P = -55/4 t + 340

(d) The owl population in 2022 will be 216

(e)  At year 2038 will be no more owl in the park

Step-by-step explanation:

* Lets explain how to solve the problem

- The owl population in 2013 was measured to be 340

- In 2017 the owl population was measured again to be 285

- The owl population is P and the time is t where t measure the numbers

 of years since 2013

(a) Let t represented by the x-coordinates of the order pairs and P

   represented by the y-coordinates of the order pairs

∵ t is measured since 2013

∴ At 2013 ⇒ t = 0

∵ The population P in 2013 was 340

∴ The first order pair is (0 , 340)

∵ The time from 2013 to 2013 = 2017 - 2013 = 4 years

∴ At 2017 ⇒ t = 4

∵ The population at 2017 is 285

∴ The second order pair is (4 , 285)

* The two ordered pairs are (0 , 340) and (4 , 285)

(b) The slope of any lines whose endpoints are (x1 , y1) and (x2 , y2)

     is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ (x1 , y1) is (0 , 340) and (x2 , y2) is (4 , 285)

∴ x1 = 0 , x2 = 4 and y1 = 340 , y2 = 285

∴ m = \frac{285-340}{4-0}=\frac{-55}{4}

* The slope is m = -55/4

∵ The slope is negative value

∴ The relation is decreasing

* The slope means the rate of decreases of the owl population was

  55/4 per year (<em>P decreased by 55/4 each year</em>)

(c) The linear equation form is y = mx + c, where m is the slope and c is

    the value of y when x = 0

∵ The population is P and represented by y

∵ The time is t and represented by t

∴ P = mt + c , c is the initial amount of population

∵ m = -55/4

∵ The initial amount of the population is 340

∴ P = -55/4 t + 340

* The model equation is P = -55/4 t + 340

(d) Lets calculate the time from 2013 to 2022

∵ t = 2022 - 2013 = 9 years

∵ P = -55/4 t + 340

∴ P = -55/4 (9) + 340 = 216.25 ≅ 216

* The owl population in 2022 will be 216

(e) If the model is accurate , then the owl population be be zero after

    t years

∵ P = -55/4 t + 340

∵ P = 0

∴ 0 = -55/4 t + 340

- Add 55/4 t to both sides

∴ 55/4 t = 340

- Multiply both sides by 4

∴ 55 t = 1360

- Divide both sides by 55

∴ t = 24.7 ≅ 25 years

- To find the year add 25 years to 2013

∵ 2013 + 25 = 2038

* At year 2038 will be no more owl in the park

8 0
3 years ago
Create an exponential to describe $100 at 2% interest compounded annually for x years
zysi [14]

Answer:

A=100(1.02)^{x}                  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=x\ years\\ P=\$100\\ r=2\%=2/100=0.02\\n=1  

substitute in the formula above

A=100(1+\frac{0.02}{1})^{1*x}  

A=100(1.02)^{x}  

8 0
4 years ago
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