Please answer with clear instructions so that i can apply this to other questions

Mathematics

1 answer:

marishachu [46]2 years ago

4 0

Answer:

1 and - 1

Step-by-step explanation:

The equation of a line passing through the origin is

y = mx ( m is the slope ( gradient ) )

y = x ← is in this form

with gradient m = 1

Parallel lines have equal gradients

Then the gradients of lines parallel to the given line is 1

Given a line with gradient m then the gradient of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{1}$ = - 1

Then the gradients of lines perpendicular to this line is - 1

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Can anyone pls help again it was 6 questions I got wrong so pls anyone, so I might post a lot but I really need this.

Strike441 [17]

To solve this we must first add up all the values.

3.29+1.28+2.49+1.59=8.65

$8.65 is our total.

Now we find 8% of the total amount. In order to do this we must first find the decimal form of the percent. It's quite simple all we have to do is move the decimal point two spaces forward. We add a 0 in front of the decimal point after that.* (True for all one digit percents)*

8.00%+ 2 spaces forward = 0.08

Then we simply multiply the percent times the total amount.

$8.65*0.08=0.69

We add the last value to the total amount and we have our answer.

$8.65+0.69=$9.34

The total amount benjamin is going to pay is $9.34 (including tax)

Hope this helps and have a great day!

5 0

3 years ago

Han wrote a proof that triangle BCD is congruent to triangle DAB. Han's proof is incomplete. Which step is missing some informat

Ede4ka [16]

Answer:

The answer is below

Step-by-step explanation:

From the image, we can see that DC is parallel to AB.

Step 1:

Alternate interior angles are angles formed at the inner corners of intersection on opposite sides of transversal when two parallel lines are intersected by a transversal.

Since Line AB is parallel to line DC and cut by transversal DB. So angles CDB and ABD are alternate interior angles and must be congruent.

Step 2:

DB ≅ BD (reflexive property of congruence)

Step 3:

∠A = ∠C = 90° (right angles, given). But to prove that both triangles are congruent, the correct step 3 is:

Since, ∠A = ∠C = 90° and angles CDB and ABD are congruent. This means that the third angles in the both triangles are also congruent. Hence, angle ADB and CBD are must be congruent.

Step 4:

BD = DB, angles CDB and ABD are congruent, angle ADB and CBD are congruent.

Therefore, By the Angle-Side-Angle Triangle Congruence Theorem, triangle BCD is congruent to triangle DAB .